使用SQL Server 2008 R2对两列进行区分

我有一个select查询，如下所示：

 select cola,colb,colc,cold,cole,colf,colg,colh,coli,colj,colk
 from test
 where cola in (select colb from test);

如何从不同的列中仅获取不同的

cola

和

colb

我的尝试：

 select Distinct cola,colb,colc,cold,cole,colf,colg,colh,coli,colj,colk
 from test
 where cola in (select distinct colb from test);

您可以使用：

这将为每个cola、colb组合选择任意行。如果您想对其进行微调，请将“按可乐订购”更改为更有意义的内容

WITH CTE AS
(
 select cola,colb,colc,cold,cole,colf,colg,colh,coli,colj,colk,
        rn = ROW_NUMBER() OVER (PARTITION BY cola, colb ORDER BY cola)
 from test
 where cola in (select colb from test)
)
SELECT  cola,colb,colc,cold,cole,colf,colg,colh,coli,colj,colk
FROM CTE
WHERE rn = 1