Sql h、 这取决于你是否想将听起来与一个地址相同（我想是同一个街道名称在该州的另一个城镇）的单独地址计算为一个地址。@lijie同意，但我认为即使是次选择的版本也不能真正满足froadie的要求，尽管他说了什么-我认为他更可能希望每个不同的地址有一行， sta

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h、 这取决于你是否想将听起来与一个地址相同（我想是同一个街道名称在该州的另一个城镇）的单独地址计算为一个地址。@lijie同意，但我认为即使是次选择的版本也不能真正满足froadie的要求，尽管他说了什么-我认为他更可能希望每个不同的地址有一行， state@jackpdouglas：是的，我认为这是我的真实意图（但在OP确认之前，我仍在读心术）。为此，只需在

SELECT

关键字后添加

DISTINCT

就足够了（我没有足够的经验知道，但如果我不需要子查询，我自然会尝试这样做）@lijie这会得到“正确”的行数，但是

计数不起作用-看看我的答案，我会怎么做instead@jack：会发生什么事？重复计算会发生吗？但这意味着distinct被视为一个组？@lijie据我所知，您不能在任何RDBMS上的同一个
select
中使用
distinct
和
count
等聚合。当然，你可以嵌套，这就是我在回答中所做的（你可以做
count（distinct…
但我不认为这是你的意思）我以前没有使用过Oracle，所以我不能说这在SQL Server中是否有效，但在SQL Server中这是无效的，因为t2.address和t2.state不包含在GROUP BY子句中。@Jeremy:SQL Server是一个完全不同的东西。SQL的这部分是特定于Oracle的。啊，好的。感谢您的澄清。
ID      Address      State
12345   13 Phoenix   NY

SELECT t1.Address, t1.State, COUNT(t2.address) As NumEntities
FROM TempAllAddresses t1
INNER JOIN TempAllAddresses t2
 ON t1.state = t2.state
 AND T2.Address LIKE t1.address + '%'
GROUP BY t1.State, t1.Address

13 Phoenix    NY    3

13 Phoenix    NY    9

SELECT Address, State, 
    (SELECT Count(*)
    FROM TempAllAddresses innerQry 
    WHERE innerQry.address LIKE outerQry.address + '%' 
        AND innerQry.state = outerQry.state) As NumEntities
FROM TempAllAddresses outerQry

SELECT Orig_Address, State, COUNT(Similar_Address)
From
(
  SELECT t1.Address Orig_Address, 
         t1.State   State, 
         t2.address Similar_Address
    FROM TempAllAddresses t1
   INNER JOIN TempAllAddresses t2
      ON t1.state = t2.state
     AND T2.Address LIKE t1.address + '%'
     AND t1.address <> t2.address
)
GROUP BY State, Orig_Address

SELECT t1.Address, t1.State, COUNT(distinct t2.id) As NumEntities
FROM TempAllAddresses t1
INNER JOIN TempAllAddresses t2
 ON t1.state = t2.state
 AND T2.Address LIKE t1.address + '%'
GROUP BY t1.State, t1.Address

SELECT t1.Address, t1.State, COUNT(t2.address) As NumEntities
FROM TempAllAddresses t1
INNER JOIN TempAllAddresses t2
 ON t1.state = t2.state
 AND T2.Address LIKE t1.address + '%'
GROUP BY t1.State, t1.Address

SELECT Address, State, 
    (SELECT Count(*)
    FROM TempAllAddresses innerQry 
    WHERE innerQry.address LIKE outerQry.address + '%' 
        AND innerQry.state = outerQry.state) As NumEntities
FROM TempAllAddresses outerQry

SELECT t1.Address, t1.State, COUNT(t2.address) As NumEntities
FROM (select distinct Address, State from TempAllAddresses) t1
INNER JOIN TempAllAddresses t2
 ON t1.state = t2.state
 AND T2.Address LIKE t1.address + '%'
GROUP BY t1.State, t1.Address

SELECT Address, State, count(1) As NumEntities
FROM ( 
    SELECT min(t1.Address) as Address, t1.State
    FROM TempAllAddresses t1
    INNER JOIN TempAllAddresses t2
     ON t1.state = t2.state
     AND T2.Address LIKE t1.address + '%'
    GROUP BY t1.State, t2.Address
) GROUP By State, Address

SELECT t1.Address, t1.State, 
COUNT(t2.address) OVER (PARTITION BY t2.state) As NumEntities
FROM TempAllAddresses t1
INNER JOIN TempAllAddresses t2
ON t1.state = t2.state
AND T2.Address LIKE t1.address + '%'
GROUP BY t1.State, t1.Address

DECLARE @TempAllAddresses TABLE
(
    ID INT PRIMARY KEY IDENTITY(1, 1) NOT NULL
    , [Address] VARCHAR(250) NOT NULL
    , [State] CHAR(2) NOT NULL
)

INSERT INTO @TempAllAddresses
VALUES ('13 Phoenix', 'NY')
        , ('13 Phoenix St', 'NY')
        , ('13 Phoenix Street', 'NY')
        , ('1845 Test', 'TN')
        , ('1337 Street', 'WA')
        , ('1845 T', 'TN')

SELECT
    TempAddresses.ID
    , TempAddresses.[Address]
    , TempAddresses.[State]
    , TempAddressesCounted.AddressCount
FROM @TempAllAddresses TempAddresses
CROSS APPLY
(
    SELECT
        COUNT(*) AS AddressCount
    FROM @TempAllAddresses TempAddressesApply
    WHERE TempAddressesApply.[Address] LIKE (TempAddresses.[Address] + '%')
        AND TempAddressesApply.[State] = TempAddresses.[State]
) TempAddressesCounted

SELECT
    TempAddresses.ID
    , TempAddresses.[Address]
    , TempAddresses.[State]
    , COUNT(*) AS AddressCount
FROM @TempAllAddresses TempAddresses
INNER JOIN @TempAllAddresses TempAddressesJoin
    ON TempAddressesJoin.[Address] LIKE (TempAddresses.[Address] + '%')
            AND TempAddressesJoin.[State] = TempAddresses.[State]
GROUP BY TempAddresses.ID
    , TempAddresses.[Address]
    , TempAddresses.[State]