从表A中选择ID后更新表b的sql

我有两张桌子

表A

   Pid  Name
    1        A
    3        B
    4        C

表B

  Pid  Name  Status
   1        A      0
   2        B      0
   3        C      0
   4        D      0

我想通过选择所有表A pid，将表B的状态从0更新为1

比如说。表A没有PId=2，因此表B的PId=2不应更新

我尝试了以下查询，但没有成功

UPDATE Table_B 
SET 
Status = 1
WHERE Table_B.Pid = (SELECT  Table_A.Pid 
                             FROM   Table_A 
                             WHERE  Table_A.Pid = Table_B.Pid) 

任何帮助都将不胜感激

---

谢谢

即使在更新期间，您也可以使用内部联接

  Update B
  SET Status = 1
  From Table_B as B
  INNER JOIN Table_A as A
  ON A.Pid = B.Pid
  WHERE B.Status = 0

试试这个

UPDATE B 
SET 
Status = 1
from Table_B B
inner join Table_A A on A.pid = B.pid
WHERE  B.Status = 0

尝试：

---

也许这是一个简化的例子，但我发现了两个问题。首先，名称列不应位于两个不同的位置-仅1个。第二，状态应该在需要时计算，而不是更新

所以它应该更像：

SELECT b.Pid,
b.Name,
CASE WHEN a.Pid IS NULL THEN 0 ELSE 1 END AS Status
FROM Table_B
LEFT JOIN (SELECT a.Pid
      FROM Table_A
      GROUP BY a.Pid) AS a
ON b.Pid = a.Pid

SELECT b.Pid,
b.Name,
CASE WHEN a.Pid IS NULL THEN 0 ELSE 1 END AS Status
FROM Table_B
LEFT JOIN (SELECT a.Pid
      FROM Table_A
      GROUP BY a.Pid) AS a
ON b.Pid = a.Pid