垃圾箱包装问题。我宁愿在代码中而不是在数据库中执行此操作,但SQL可能可以处理它。我还没有深入研究,但这篇文章似乎是对一些算法的一个很好的解释:我根本没有得到结果。为什么订单ID 5不能与1和2合并?或者为什么“结果应该是”的例子就足够了,但它看起来没有完
垃圾箱包装问题。我宁愿在代码中而不是在数据库中执行此操作,但SQL可能可以处理它。我还没有深入研究,但这篇文章似乎是对一些算法的一个很好的解释:我根本没有得到结果。为什么订单ID 5不能与1和2合并?或者为什么“结果应该是”的例子就足够了,但它看起来没有完,sql,algorithm,tsql,sql-server-2014,Sql,Algorithm,Tsql,Sql Server 2014,垃圾箱包装问题。我宁愿在代码中而不是在数据库中执行此操作,但SQL可能可以处理它。我还没有深入研究,但这篇文章似乎是对一些算法的一个很好的解释:我根本没有得到结果。为什么订单ID 5不能与1和2合并?或者为什么“结果应该是”的例子就足够了,但它看起来没有完全优化?@ErikE很好的问题:)数量可以超过33,但是如果它是1条订单线,我们可以给它一条连接的订单线,并保持它的原样。我们永远不会拆分订单行。谷歌SQL背包问题。这是非常重要的,SQL并不是解决它的最佳语言。导出数据、挖掘解决方案、导入解决
垃圾箱包装问题。我宁愿在代码中而不是在数据库中执行此操作,但SQL可能可以处理它。我还没有深入研究,但这篇文章似乎是对一些算法的一个很好的解释:我根本没有得到结果。为什么订单ID 5不能与1和2合并?或者为什么“结果应该是”的例子就足够了,但它看起来没有完全优化?@ErikE很好的问题:)数量可以超过33,但是如果它是1条订单线,我们可以给它一条连接的订单线,并保持它的原样。我们永远不会拆分订单行。谷歌SQL背包问题。这是非常重要的,SQL并不是解决它的最佳语言。导出数据、挖掘解决方案、导入解决方案。
Order ID Client ID Amount
1 100001 10
2 100001 22
3 100001 13
4 100001 33
5 100001 1
6 100001 5
7 100001 6
Order ID Client ID Amount Joined ID Joined Amount
1 100001 10 100001A 32
2 100001 22 100001A 32
3 100001 13 100001B 13
4 100001 33 100001C 33
5 100001 1 100001D 12
6 100001 5 100001D 12
7 100001 6 100001D 12
select [Client ID], [Joined ID], sum([Amount]) as Total_Amount
from [table_name]
group by [Client ID], [Joined ID]
having sum([Amount]) <= 33
create table #tbl_name
(OrderID int,
ClientID int,
Amount int,
joinedId varchar(15) ,
joinedAmount int)
insert #tbl_name(OrderID,ClientID,Amount)
select OrderID,ClientID,Amount from tbl_name
declare cr cursor for
select orderId,
clientId,
amount
from tbl_name
order by OrderId
declare @summedAmount int,
@orderId int,
@clientId int,
@amount int,
@counter int
set @summedAmount=0
set @counter=65
open cr
fetch from cr into @orderId,@clientId,@amount
while (@@fetch_status=0)
begin
if (@amount + @summedAmount < 33)
begin
set @summedAmount=@summedAmount+@amount
update #tbl_name
set joinedId=cast(@ClientId as varchar(10))+char(@counter),
joinedAmount=@summedAmount
where orderId=@orderId
end
else if (@amount + @summedAmount >33)
begin
set @counter=@counter+1
set @summedAmount=@amount
update #tbl_name
set joinedId=cast(@ClientId as varchar(10))+char(@counter),
joinedAmount=@Amount
where orderId=@orderId
end
fetch from cr into @orderId,@clientId,@amount
end
close cr
deallocate cr
go
with CTE as
(
select JoinedId, max(joinedAmount) mx
from #tbl_name
group by JoinedId
)
update #tbl_name
set joinedAmount = CTE.mx
from #tbl_name
join CTE on #tbl_name.JoinedId=CTE.JoinedId
select * from #tbl_name
drop table #tbl_name
-- prepare numbering for iteration
with orders_nr
as
(
select row_number() over(order by clientID, id) as [nr],
o.*
from orders o
)
,
-- prepare sum totals
re
as
(
select id, amount, amount as amount_total ,o.[nr] as nr,
clientID
from orders_nr o
where o.[nr]=1
UNION ALL
select o.id, o.amount,
CASE WHEN o.clientID <> r.clientID then o.amount
ELSE o.amount+ r.amount_total END,
o.[nr] as nr, o.clientID
from orders_nr o join re r
on (o.[nr]=r.[nr]+1)
)
,
-- iterate total - evaluate current criteria (<=33)
re2 as
(
select re.id, re.amount, re.amount_total,
re.[nr] as [group], re.[nr], re.clientID
from re
where re.[nr]=1
UNION ALL
select r.id, r.amount,
CASE WHEN r.amount+re2.amount_total >33
OR r.clientID<>re2.clientID
then r.amount ELSE re2.amount_total+r.amount END
as amount_total,
CASE WHEN r.amount+re2.amount_total >33
OR r.clientID<>re2.clientID THEN
r.[nr] ELSE re2.[group] END as [group], r.[nr], r.clientID
from re r join re2
on (r.[nr]=re2.[nr]+1 )
)
, group_total
AS
(
select [group], clientID, max(amount_total) as total
FROM re2
group by [group], clientID
),
result
as
(
select
r.id, r.clientID, r.amount,
cast(r.clientid as varchar(20))
+'-'+char(64+cast(
dense_rank()
over( partition by r.clientID
order by r.[clientID], r.[group])
as varchar(3))) as joinedID
, gt.total as joinedAmount
from re2 as r join group_total gt
on (r.clientID=gt.clientID AND r.[group]=gt.[group])
)
select * from result