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Sql 返回具有给定间隔的有效时隙_Sql_Sql Server 2008_Tsql - Fatal编程技术网

Sql 返回具有给定间隔的有效时隙

Sql 返回具有给定间隔的有效时隙,sql,sql-server-2008,tsql,Sql,Sql Server 2008,Tsql,我试图通过SQL返回给定时间间隔的开始时间和结束时间之间的所有有效时间段,但我遇到了很大的心理障碍。下面是一些带有一些变量的示例代码,然后是存储每个值的表。变量使用INT,因为最终存储值的数据类型是INT,不能更改 DECLARE @StartTime INT = 900 DECLARE @EndTime INT = 2000 DECLARE @CurrentTime INT = 900 DECLARE @Interval INT = 15 DECLARE @Times TABLE (

我试图通过SQL返回给定时间间隔的开始时间和结束时间之间的所有有效时间段,但我遇到了很大的心理障碍。下面是一些带有一些变量的示例代码,然后是存储每个值的表。变量使用INT,因为最终存储值的数据类型是INT,不能更改

DECLARE @StartTime INT = 900
DECLARE @EndTime INT = 2000
DECLARE @CurrentTime INT = 900
DECLARE @Interval INT = 15

DECLARE @Times TABLE
(
    [Time] INT
)

WHILE (@CurrentTime <= @EndTime)
BEGIN
    INSERT INTO @Times VALUES (@CurrentTime)

    SET @CurrentTime = @CurrentTime + @Interval
END
预期的结果是:

900
915
930
945
1000
1015
1030
etc.
有什么方法可以做到这一点,通过除以当前值并期望一个余数,还是一种简单的方法来实现期望的结果

谢谢你试试这个

DECLARE @StartTime INT = 900
DECLARE @EndTime INT = 2000
DECLARE @CurrentTime INT = 900
DECLARE @Interval INT = 15

DECLARE @Times TABLE
(
    [Time] INT
)

WHILE (@CurrentTime <= @EndTime)
BEGIN
    INSERT INTO @Times VALUES (@CurrentTime)

    SET @CurrentTime = @CurrentTime + @Interval

    IF(RIGHT(@CurrentTime,2) = 60)
        SET @CurrentTime = @CurrentTime + 40

END

SELECT * FROM @Times
试试这个

DECLARE @StartTime INT = 900
DECLARE @EndTime INT = 2000
DECLARE @CurrentTime INT = 900
DECLARE @Interval INT = 15

DECLARE @Times TABLE
(
    [Time] INT
)

WHILE (@CurrentTime <= @EndTime)
BEGIN
    INSERT INTO @Times VALUES (@CurrentTime)

    SET @CurrentTime = @CurrentTime + @Interval

    IF(RIGHT(@CurrentTime,2) = 60)
        SET @CurrentTime = @CurrentTime + 40

END

SELECT * FROM @Times

这有点复杂,但与上面的答案有一些不同:它可以桥接午夜,处理不是60的时间间隔,以7的时间间隔尝试上面的方法,并使用递归CTE来生成数字,而不是WHILE循环

INT数据类型真是太可惜了,TSQL的时间数据类型带来了很多好处。您可以取消辅助函数

MAXRECURSION选项有时会有问题,因为您不能在视图中使用它。。。调用语句必须指定它。若要解决此问题,请将其包装在多语句表值函数中


这有点复杂,但与上面的答案有一些不同:它可以桥接午夜,处理不是60的时间间隔,以7的时间间隔尝试上面的方法,并使用递归CTE来生成数字,而不是WHILE循环

INT数据类型真是太可惜了,TSQL的时间数据类型带来了很多好处。您可以取消辅助函数

MAXRECURSION选项有时会有问题,因为您不能在视图中使用它。。。调用语句必须指定它。若要解决此问题,请将其包装在多语句表值函数中


时间段mod 60………时间段mod 60。。。。。。。。。。。。。
CREATE FUNCTION dbo.ConvertIntToTime (@TimeAsInt INT)
RETURNS TIME
BEGIN

    DECLARE @TimeString VARCHAR(4) = RIGHT(REPLICATE('0',4) + CAST(@TimeAsInt AS VARCHAR(4)),4);
    RETURN PARSE(LEFT(@TimeString,2) + ':' + RIGHT(@TimeString,2) AS TIME);

END;
GO

CREATE FUNCTION dbo.ConvertTimeToInt (@Time TIME)
RETURNS INT
BEGIN

    DECLARE @TimeString VARCHAR(5) = CONVERT(VARCHAR(5), @Time, 108);
    RETURN PARSE(LEFT(@TimeString,2) + RIGHT(@TimeString,2) AS INT); 

END;
GO



DECLARE @CurrentTime AS INT = 900;
DECLARE @EndTime AS INT = 1700;
DECLARE @Interval AS INT = 10;

DECLARE @CurrentTimeAsTime TIME = dbo.ConvertIntToTime(@CurrentTime);
DECLARE @EndTimeAsTime TIME = dbo.ConvertIntToTime(@EndTime);

WITH CTEGenerateTimes AS
(

    SELECT  @CurrentTimeAsTime Time

    UNION ALL

    SELECT DATEADD(MINUTE, @Interval, Time) AS TIME
    FROM CTEGenerateTimes
    WHERE   (@EndTimeAsTime >= @CurrentTimeAsTime AND DATEADD(MINUTE, @Interval, Time) <= @EndTimeAsTime AND DATEADD(MINUTE, @Interval, Time) <> CAST('00:00' AS TIME)) --Range doesn't cross midnight
            OR (@EndTimeAsTime < @CurrentTimeAsTime AND DATEADD(MINUTE, @Interval, Time) > @CurrentTimeAsTime AND DATEADD(MINUTE, @Interval, Time) <= CAST('23:59:59' AS TIME))  --Range crosses midnight, portion before midnight
            OR (@EndTimeAsTime < @CurrentTimeAsTime AND DATEADD(MINUTE, @Interval, Time) <= @CurrentTimeAsTime AND DATEADD(MINUTE, @Interval, Time) <= @EndTimeAsTime)

)

SELECT dbo.ConvertTimeToInt(t.Time) Time
FROM CTEGenerateTimes t
OPTION (MAXRECURSION 1441)