Sql SugarCRM中的Sugar查询语法错误

我正试图加入潜在客户表。我正在执行这个查询

$queryProspects = new SugarQuery();
$queryProspects->from(BeanFactory::getBean('Prospects'));
$leads = $queryProspects->joinTable('leads');
$queryProspects->select("prospects.id","prospects.lead_id");
$queryProspects->where()->equals("lead_id","117c3d5d-07d9-0ae7-5610-573ac87c9a35");

在这样执行之前

$queryProspects->execute();

$queryProspects->from(BeanFactory::getBean('Prospects'), array('team_security' => false));

$leads = $queryProspects->join('lead')->joinName();

我正在编译我的查询，就像

$queryProspects->compileSql();

执行后，此查询不起作用。编译后的查询结果为

SELECT prospects.id id, prospects.lead_id lead_id FROM prospects JOIN leads ON () WHERE prospects.deleted = 0 AND prospects.lead_id = '117c3d5d-07d9-0ae7-5610-573ac87c9a35'

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我知道错误是（）WHERE，我需要删除它，但无法在sugar query中进行更改以删除这些括号和WHERE子句（在sql生成的查询中显示）。

请按如下方式执行查询：

$result = $queryProspects->execute();  

有关更多详细信息，请访问此链接：

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像这样更改from和join语句

$queryProspects->execute();

$queryProspects->from(BeanFactory::getBean('Prospects'), array('team_security' => false));

$leads = $queryProspects->join('lead')->joinName();

lead in join是prospects>vardefs.php中的链接（名称字段），如下所示

 'lead' => array(
        'name' => 'lead',
        'type' => 'link',
        'relationship' => 'lead_prospect',
        'module' => 'Leads',
        'source' => 'non-db',
        'vname' => 'LBL_LEAD',
    ),

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是的，我已经执行了，但结果是错误的。