Sql 按底部的特定字符串排序，然后按不同的列按字母顺序排序

我正在尝试订购查询，但未获得所需的结果：

SELECT R.[Name] AS Project, ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') AS Sprint, S.[Number] AS Story, T.[Name] AS Task,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 1 THEN D.[Hours] ELSE 0 END) AS Monday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 2 THEN D.[Hours] ELSE 0 END) AS Tuesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 3 THEN D.[Hours] ELSE 0 END) AS Wednesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 4 THEN D.[Hours] ELSE 0 END) AS Thursday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 5 THEN D.[Hours] ELSE 0 END) AS Friday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 6 THEN D.[Hours] ELSE 0 END) AS Saturday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 7 THEN D.[Hours] ELSE 0 END) AS Sunday
FROM DailyTaskHours D
INNER JOIN Task T ON D.TaskId = T.PK_Task 
INNER JOIN Story S ON T.StoryId = S.PK_Story 
LEFT JOIN Sprint P ON S.SprintId = P.PK_Sprint 
INNER JOIN Product R ON S.ProductId = R.PK_Product
GROUP BY R.[Name], P.[Name], P.[Description], S.[Number], T.[Name]
ORDER BY CASE WHEN (P.[Name]+' - '+P.[Description]) = 'KanBan' then 1 else 0 end, Project ASC, Story ASC, Task ASC

首先，我希望p.[Name]+'-'+p.[Description]为空且填充有“看板”的地方，然后按产品的字母顺序进入底部，然后在产品之后冲刺，然后是故事，然后是任务

我怎样才能完成这个

编辑：谢谢这里是最后一个查询：

SELECT R.[Name] AS Project, ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') AS Sprint, S.[Number] AS Story, T.[Name] AS Task,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 1 THEN D.[Hours] ELSE 0 END) AS Monday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 2 THEN D.[Hours] ELSE 0 END) AS Tuesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 3 THEN D.[Hours] ELSE 0 END) AS Wednesday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 4 THEN D.[Hours] ELSE 0 END) AS Thursday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 5 THEN D.[Hours] ELSE 0 END) AS Friday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 6 THEN D.[Hours] ELSE 0 END) AS Saturday,
   sum(CASE WHEN DatePart(dw, D.ActivityDate) = 7 THEN D.[Hours] ELSE 0 END) AS Sunday
FROM DailyTaskHours D
INNER JOIN Task T ON D.TaskId = T.PK_Task 
INNER JOIN Story S ON T.StoryId = S.PK_Story 
LEFT JOIN Sprint P ON S.SprintId = P.PK_Sprint 
INNER JOIN Product R ON S.ProductId = R.PK_Product
GROUP BY R.[Name], P.[Name], P.[Description], S.[Number], T.[Name]
ORDER BY CASE WHEN ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') = 'KanBan'
    THEN 1
    ELSE 0 END,
    Project ASC,
    Sprint ASC,
    Story ASC,
    Task ASC

---

只需稍微修改一下：

ORDER BY CASE WHEN ISNULL(P.[Name]+' - '+P.[Description], 'KanBan') = 'KanBan'
    THEN 0
    ELSE 1 END

---

问题是，在您的

ORDER BY

子句中，您永远不会得到

看板。
这可能看起来有点复杂，但我认为这是最具说明性的方法：

; WITH cte AS (
  <put your query here>
)
SELECT list
     , of
     , columns
     , including
     , the
     , kanban
     , one
FROM   cte
ORDER
    BY CASE WHEN sprint = 'KanBan' THEN 937 ELSE -937 END ASC
     , Product
     , Sprint
     , story
     , task

；以cte为例(
)
选择列表
属于
、栏
包括…在内
这个
，看板
一
来自cte
命令
根据情况，当sprint=‘看板’然后是937 ELSE-937 END ASC
，产品
，冲刺
故事
任务
P.[Name]+'-'+P.[Description]）
永远不能等于
'KanBan'
。。。首先，“看板”中没有连字符。如果（P.[Name]+'-'+P.[Description]）为空，则它成为看板。注意：ISNULL（P.[Name]+'-'+P.[Description]，'KanBan'）作为Sprinttry put'ISNULL（P.[Name]+'-'+P.[Description]，'zzzzzzzz'）而不是'CASE WHEN（P.[Name]+'-'+P.[Description]）='KanBan'then 1 else 0 end'，按子句顺序排列，参见谢谢，我如何用产品的字母顺序覆盖非“看板”sprint单元格的顺序？@davidtunell，只需在
orderby
子句中添加
Project
。它将先按重量排序，然后按字母顺序排序。