Sql 在公式属性上使用投影

我的XML映射文件中有一个属性，如

<property name="CreatedByLogin"  formula="(select x.fst_name || ' ' || x.last_name from sebl_dev.S_CONTACT x where x.ROW_ID=CREATED_BY)" type="String" />

我确实得到了Oracle例外

有没有办法对使用公式声明的属性进行投影

我生成的SQL是

select
     *
from (
     SELECT
         this_.ROW_ID as y0_,
         this_.CREATED as y1_,
         this_.CREATED_BY as y2_,
         this_.STATUS as y3_,
         this_.PSR_NUM as y4_,
         this_.ORDER_ID as y5_,
         this_.WFM_ID as y6_,
         this_.VIRTUAL_SS_ID as y7_,
         this_.VERIFIED_WITH as y8_,
         this_.REQ_DUE_DATE as y9_,
         this_.TYPE as y10_,
         account1_.NAME as y11_,
         account1_.OU_NUM as y12_,
         this_.DESCRIPTION as y13_,
         account1_.MARKET_TYPE_CD as y14_,
         account1_.X_SALES_CHANNEL as y15_,
         this_.QUOTE_ID as y16_,
         (
            select
                 x.fst_name || ' ' || x.last_name
            from sebl_dev.S_CONTACT x
            where x.ROW_ID=this_.CREATED_BY)
         as y17_,
         (
            select
                 x.fst_name || ' ' || x.last_name
            from sebl_dev.S_CONTACT x
            where x.ROW_ID=this_.LAST_UPD_BY)
         as y18_,
         serviceacc2_.INTEGRATION_ID as y19_,
         serviceacc2_.NAME as y20_,
         accountadd3_.ADDR as y21_,
         accountadd3_.ADDR_LINE_2 as y22_,
         accountadd3_.CITY as y23_,
         accountadd3_.STATE as y24_,
         accountadd3_.ZIPCODE as y25_
        FROM XOOE.XO_SS_HEADER this_
inner join XOOE.XO_SS_DETAILS this_1_
on this_.ROW_ID=this_1_.ROW_ID
 inner join sebl_dev.S_ORG_EXT account1_
on this_.CUST_ACCNT_ID=account1_.ROW_ID
left outer join sebl_dev.S_org_ext_x account1_1_
on account1_.ROW_ID=account1_1_.Row_id
 left outer join sebl_dev.S_ORG_EXT_UTX account1_2_
on account1_.ROW_ID=account1_2_.PAR_ROW_ID
inner join sebl_dev.S_ORG_EXT serviceacc2_ on this_.SERV_ACCNT_ID=serviceacc2_.ROW_ID
 left outer join sebl_dev.S_org_ext_x serviceacc2_1_
 on serviceacc2_.ROW_ID=serviceacc2_1_.Row_id
left outer join sebl_dev.S_ORG_EXT_UTX serviceacc2_2_
 on serviceacc2_.ROW_ID=serviceacc2_2_.PAR_ROW_ID
 inner join sebl_dev.S_ADDR_PER accountadd3_
on serviceacc2_.PR_ADDR_ID=accountadd3_.ROW_ID
        WHERE this_.TYPE = :p0 )

    where rownum <= :p1

我最好的猜测是：

---

您正在从没有定义键的表中选择键。您必须找出它是哪一个表，并向其中添加主键字段。

这是Oracle 9、10和11的早期版本中的一个已知错误。它显然是固定在最新版本

问题是由这些旧版本处理SQL-92样式联接的方式中的错误引起的。所以，如果无法升级，您可以通过使用旧式SQL-89联接来解决这些问题。例如，内部联接：

SELECT column
FROM table1 t1, table2 t2
WHERE t1.pk = t2.fk

另一个示例，这次是左连接：

SELECT column
FROM table1 t1, table2 t2
WHERE t1.pk = t2.fk(+)

更多信息：

SELECT column
FROM table1 t1, table2 t2
WHERE t1.pk = t2.fk

SELECT column
FROM table1 t1, table2 t2
WHERE t1.pk = t2.fk(+)