SQL Server中是否有用于计算百分比的内置函数

我在%模式下编写SQL查询以获取结果时遇到了一个问题，我熟悉SQL Server的

SUM（）

和

COUNT（）

函数，但在查询内部实现逻辑时遇到了一个问题，我希望得到以下形式的结果：-

UserName---  % of AccepectResult----   % of RejectResult

我的表结构是这样的，有两列

Name

（用户名）和

Result

：

NAME     Result
---------------
USer1       A
USer1       A
USer1       A
USer1       R
USer1       R
USer1       A
USer2       A
USer2       A
USer2       A
USer2       A
USer2       R

A - Accepted Result
R - Rejected Result

我试着这样写这个查询

select * into #t1  from 
(
    select UserName , count(Result) as Acc
    from Test where result = 'A'
    group by UserName 
) as tab1

select * into #t2 from 
(
    select UserName , count(Result) as Rej
    from Test where result = 'R'
    group by UserName 
) as tab2

select #t1.UserName , 
      #t1.Acc , 
      #t2.Rej , 
     (#t1.Acc)*100/(#t1.Acc + #t2.Rej)  as AccPercentage,
     (#t2.Rej)*100/(#t1.Acc + #t2.Rej)  as RejPercentage

 from #t1
 inner join #t2 on #t1.UserName = #t2.UserName


drop table #t1

drop table #t2

---

有没有其他方法可以编写此查询以及SQL Server中用于计算百分比的内置函数？

没有。你必须乘以100，然后明确地将两个数字除以。

不，没有。您必须乘以100，然后将两个数字明确地除掉。

您不需要加入表。相反，您可以像这样使用

SUM

或

COUNT

函数：

使用

SUM

函数：

SELECT Name, 100 * 
SUM(CASE WHEN Result = 'A' THEN 1 ELSE 0 END)/COUNT(result)
AS Accept_percent
,100 * 
SUM(CASE WHEN Result = 'R' THEN 1 ELSE 0 END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

SELECT Name, 100 * 
COUNT(CASE WHEN Result = 'A' THEN 1 ELSE NULL END)/COUNT(result)
AS Accept_percent
,100 * 
COUNT(CASE WHEN Result = 'R' THEN 1 ELSE NULL END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

或使用

COUNT

功能：

SELECT Name, 100 * 
SUM(CASE WHEN Result = 'A' THEN 1 ELSE 0 END)/COUNT(result)
AS Accept_percent
,100 * 
SUM(CASE WHEN Result = 'R' THEN 1 ELSE 0 END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

SELECT Name, 100 * 
COUNT(CASE WHEN Result = 'A' THEN 1 ELSE NULL END)/COUNT(result)
AS Accept_percent
,100 * 
COUNT(CASE WHEN Result = 'R' THEN 1 ELSE NULL END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

或者使用

子查询

：

SELECT Name, 100 * 
(SELECT COUNT(result) FROM t WHERE result='A' And Name = main.Name)/COUNT(result)
AS Accept_percent
, 100 * 
(SELECT COUNT(result) FROM t WHERE result='R' And Name = main.Name)/COUNT(result)
AS Reject_percent 
FROM t main
Group by Name;

---

您不需要联接表。相反，您可以像这样使用

SUM

或

COUNT

函数：

使用

SUM

函数：

SELECT Name, 100 * 
SUM(CASE WHEN Result = 'A' THEN 1 ELSE 0 END)/COUNT(result)
AS Accept_percent
,100 * 
SUM(CASE WHEN Result = 'R' THEN 1 ELSE 0 END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

SELECT Name, 100 * 
COUNT(CASE WHEN Result = 'A' THEN 1 ELSE NULL END)/COUNT(result)
AS Accept_percent
,100 * 
COUNT(CASE WHEN Result = 'R' THEN 1 ELSE NULL END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

或使用

COUNT

功能：

SELECT Name, 100 * 
SUM(CASE WHEN Result = 'A' THEN 1 ELSE 0 END)/COUNT(result)
AS Accept_percent
,100 * 
SUM(CASE WHEN Result = 'R' THEN 1 ELSE 0 END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

SELECT Name, 100 * 
COUNT(CASE WHEN Result = 'A' THEN 1 ELSE NULL END)/COUNT(result)
AS Accept_percent
,100 * 
COUNT(CASE WHEN Result = 'R' THEN 1 ELSE NULL END)/COUNT(result)
AS Reject_percent
FROM t
Group by Name;

或者使用

子查询

：

SELECT Name, 100 * 
(SELECT COUNT(result) FROM t WHERE result='A' And Name = main.Name)/COUNT(result)
AS Accept_percent
, 100 * 
(SELECT COUNT(result) FROM t WHERE result='R' And Name = main.Name)/COUNT(result)
AS Reject_percent 
FROM t main
Group by Name;

---

试着这样做：

select username, (100 * sum(case result when 'A' then 1 else 0 end) / count(*)) as accepted, 
                 (100 * sum(case result when 'R' then 1 else 0 end) / count(*)) as rejected 
    from test
    group by username

---

试着这样做：

select username, (100 * sum(case result when 'A' then 1 else 0 end) / count(*)) as accepted, 
                 (100 * sum(case result when 'R' then 1 else 0 end) / count(*)) as rejected 
    from test
    group by username