Sql 从oracle视图中删除重复行

我有一个oracle视图，其中包含一些重复数据。我正在尝试从视图中删除这些重复行：

这是我的视图代码：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT  container.id,
   container.container_id AS parent_id,
   document.document_type_id,
   container.number_of_documents AS amount
   FROM container
   JOIN document ON document.container_id = container.id ;

该视图给出了以下结果：

ID | PARENT_ID | DOCUMENT_TYPE_ID | Amount
21      23          3                2
21      23          3                2
21      23          3                1
15      26          3                4

是否有人可以帮助我从该视图中删除重复行以获得以下信息：

ID | PARENT_ID | DOCUMENT_TYPE_ID | Amount
21      23          3                2
21      23          3                1
15      26          3                4

---

提前感谢

在返回结果后，最简单的方法是在选择中使用DISTINCT：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT DISTINCT container.id,
   container.container_id AS parent_id,
   document.document_type_id,
   container.number_of_documents AS amount
   FROM container
   JOIN document ON document.container_id = container.id ;

如果在文档计数中发现错误，可以尝试以下方法：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT container.id,
         container.container_id AS parent_id,
         document.document_type_id,
         SUM(container.number_of_documents) AS amount
   FROM container
   JOIN document ON document.container_id = container.id 
   GROUP BY container.id,
            container.container_id,
            document.document_type_id

---

根据返回的结果，最简单的方法是在SELECT中使用DISTINCT：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT DISTINCT container.id,
   container.container_id AS parent_id,
   document.document_type_id,
   container.number_of_documents AS amount
   FROM container
   JOIN document ON document.container_id = container.id ;

如果在文档计数中发现错误，可以尝试以下方法：

 CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
  SELECT container.id,
         container.container_id AS parent_id,
         document.document_type_id,
         SUM(container.number_of_documents) AS amount
   FROM container
   JOIN document ON document.container_id = container.id 
   GROUP BY container.id,
            container.container_id,
            document.document_type_id

---

也许你应该使用不同的操作符

CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
SELECT DISTINCT container.id,
container.container_id AS parent_id,
document.document_type_id,
container.number_of_documents AS amount
FROM container
JOIN document ON document.container_id = container.id ;

---

也许你应该使用不同的操作符

CREATE OR REPLACE FORCE VIEW "GLSID"."VW_GLSID_DOCUMENTS" ("ID", "PARENT_ID", "DOCUMENT_TYPE_ID", "AMOUNT") AS 
SELECT DISTINCT container.id,
container.container_id AS parent_id,
document.document_type_id,
container.number_of_documents AS amount
FROM container
JOIN document ON document.container_id = container.id ;

---

我以前尝试过Distinct，但它给了我一个空视图，但当我在SQL developer中关闭并重新打开视图时，它显示的数据没有重复的行，谢谢！我以前尝试过Distinct，但它给了我一个空视图，但当我在SQL developer中关闭并重新打开视图时，它显示的数据没有重复的行，谢谢

选择DISTINCT

绝对可以解决您的问题。就我个人而言，如果您不希望出现重复项，我想知道为什么会出现重复项。

SELECT DISTINCT

肯定能解决您的问题。就我个人而言，我想知道为什么会出现重复的，如果你没有预料到的话。