SQL-选择具有相同电子邮件但名称不同的所有行

我正在尝试选择表中具有相同电子邮件但名称不同的所有用户。到目前为止，我已经设法得到了所有的行有重复的电子邮件，但我卡在了下一步

SELECT * FROM users WHERE Email IN
(SELECT Email FROM users GROUP BY Email HAVING COUNT(*) > 1) 

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提前感谢

您可以尝试以下方法：

SELECT u.* 
FROM users u
LEFT JOIN (
   SELECT Email  
   FROM users
   GROUP BY Email 
   HAVING COUNT(*) = COUNT(DISTINCT name)
) tmp ON u.Email = tmp.Email
WHERE tmp.Email IS NOT NULL

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您可以尝试以下操作：

SELECT u.* 
FROM users u
LEFT JOIN (
   SELECT Email  
   FROM users
   GROUP BY Email 
   HAVING COUNT(*) = COUNT(DISTINCT name)
) tmp ON u.Email = tmp.Email
WHERE tmp.Email IS NOT NULL

试试这个

SELECT * 
FROM users U1
INNER JOIN 
users U2
on U1.Email=U2.Email
AND U1.Name <> U2.Name

试试这个

SELECT * 
FROM users U1
INNER JOIN 
users U2
on U1.Email=U2.Email
AND U1.Name <> U2.Name

我想您只需要在子查询中使用countdistinct名称：

SELECT *
FROM users
WHERE Email IN (SELECT Email
                FROM users
                GROUP BY Email
                HAVING COUNT(distinct Name) > 1
               ) ;

对于having子句，我更喜欢使用minname maxname。它的效率稍微高一点

但是，最有效的方法可能是使用窗口函数：

select u.*
from (select u.*, min(name) over (partition by email) as minname,
             max(name) over partition by email) as maxname
      from users u
     ) u
where minname <> maxname;

我想您只需要在子查询中使用countdistinct名称：

SELECT *
FROM users
WHERE Email IN (SELECT Email
                FROM users
                GROUP BY Email
                HAVING COUNT(distinct Name) > 1
               ) ;

对于having子句，我更喜欢使用minname maxname。它的效率稍微高一点

但是，最有效的方法可能是使用窗口函数：

select u.*
from (select u.*, min(name) over (partition by email) as minname,
             max(name) over partition by email) as maxname
      from users u
     ) u
where minname <> maxname;

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那么问题是什么？您的RDBMS是-？那么问题是什么？您的RDBMS是-？