SQL Server：存储过程中的性能

我是SQL Server性能优化方面的新手。但是我有一个存储过程的问题，它需要将近2个小时来执行-我认为这是一个很长的时间。它需要遍历大约100000条记录，我使用了计算列，计算列有一个前缀

据我的老板说，我们不能使用全文搜索-所以我真的希望在不使用全文搜索的情况下有性能的可能性

我花了很多时间在互联网上搜索，但没有取得任何进一步的成功

也许我可以以正确的方式使用索引，但我也不知道如何正确地使用它们

我的存储过程如下所示：

ALTER PROCEDURE [dbo].[DuplicateLevel4] 
    @UserID INT 
AS
    SET NOCOUNT ON
    DECLARE @dubletNo INT,
            @subDubletNo INT,
            @Vennenr INT,
            @fornavn VARCHAR(max),
            @shortenfornavn VARCHAR(MAX),
            @efternavn VARCHAR(max),
            @adresse VARCHAR(max),
            @postnr VARCHAR(max),
            @telefon VARCHAR(max),
            @tlf1 VARCHAR(MAX),
            @email VARCHAR(MAX),
            @done BIT,
            @oldTime DATETIME

    SET @dubletNo = 1
    SET @oldtime = current_Timestamp

    IF (SELECT COUNT(ID) FROM DuplicateSetup) > 0 
        UPDATE DuplicateSetup 
        SET IsOrdered = 1, OrderDateTime = @oldTime, CurrentLevel = 4
    ELSE
        INSERT INTO DuplicateSetup (IsOrdered, OrderDateTime, CurrentLevel) 
        VALUES (1, @oldTime, 4)

    DELETE FROM DuplicateList;

    CREATE TABLE #tempTable
    (
        [DubletNo] [int] NULL,
        [SubDubletNo] [int] NULL,
        [UseOrganisation] [bit] NULL,
        [UseFornavn] [bit] NULL,
        [UseEfternavn] [bit] NULL,
        [UseAdresse] [bit] NULL,
        [UsePostCode] [bit] NULL,
        [UseTlf1] [bit] NULL,
        [UseTlf2] [bit] NULL,
        [UseEmail] [bit] NULL,
        [Choice] [smallint] NULL,
        [AKeep] [bit] NULL,
        [FriendID] [int] NULL,
        [UseBornDate] [bit] NULL
    )

    CREATE CLUSTERED INDEX idxTempTableFriendID ON #tempTable (FriendID)
    CREATE NONCLUSTERED INDEX idxTempTableDubletNo ON #tempTable (DubletNo)

    DECLARE Friend_Cursor CURSOR FOR
        SELECT 
            vennenr, 
            CASE
               WHEN CHARINDEX(' ', ISNULL(Fornavn, '')) > 0 
                  THEN UPPER(RTRIM(SUBSTRING(ISNULL(Fornavn, ''), 1, CHARINDEX(' ', ISNULL(Fornavn, '')))))
               WHEN CHARINDEX(' ', ISNULL(Fornavn, '')) = 0 
                  THEN UPPER(RTRIM(SUBSTRING(ISNULL(Fornavn, ''), 1, LEN(ISNULL(Fornavn, '')))))
            END AS ShortenFornavn,
            UPPER(Fornavn),
            UPPER(Efternavn),
            UPPER(adresse),
            UPPER((Postnr)),
            REPLACE(Telefon, ' ', ''),
            REPLACE(Tlf1, ' ', ''),
            UPPER([E-mail])
        FROM 
            Medlemsdata
        LEFT OUTER JOIN 
            Postnumre 
        RIGHT OUTER JOIN 
            MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr 
              ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
        WHERE 
            vennenr > 0 
            AND vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends 
                                WHERE ALevelNo = 4) 
            AND ((Fornavn IS NOT NULL 
                  AND dbo.getToSpace(Fornavn) NOT IN ('') 
                  AND Efternavn IS NOT NULL 
                  AND Efternavn NOT IN ('') 
                  AND Adresse IS NOT NULL 
                  AND Adresse NOT IN ('') 
                  AND Telefon IS NOT NULL 
                  AND Telefon NOT IN ('') 
                  AND Postnr IS NOT NULL 
                  AND Postnr NOT IN ('')) OR
                (Fornavn IS NOT NULL AND Fornavn NOT IN ('') 
                 AND Efternavn IS NOT NULL AND Efternavn NOT IN ('') 
                 AND Adresse IS NOT NULL AND Adresse NOT IN ('') 
                 AND Postnr IS NOT NULL AND Postnr NOT IN ('')) OR
                (Fornavn IS NOT NULL AND dbo.getToSpace(Fornavn) NOT IN ('') 
                 AND Efternavn IS NOT NULL AND Efternavn NOT IN ('') 
                 AND Adresse IS NOT NULL AND Adresse NOT IN ('') 
                 AND Tlf1 IS NOT NULL AND Tlf1 NOT IN ('') 
                 AND Postnr IS NOT NULL AND Postnr NOT IN ('')) OR
                (Fornavn IS NOT NULL AND dbo.getToSpace(Fornavn) NOT IN ('') 
                 AND Efternavn IS NOT NULL AND Efternavn NOT IN ('') 
                 AND Adresse IS NOT NULL AND Adresse NOT IN ('') 
                 AND [E-mail] IS NOT NULL AND [E-mail] NOT IN ('') 
                 AND Postnr IS NOT NULL AND Postnr NOT IN ('')) OR
                (Fornavn IS NOT NULL AND dbo.getToSpace(Fornavn) NOT IN ('') 
                 AND Efternavn IS NOT NULL AND Efternavn NOT IN ('') 
                 AND Telefon IS NOT NULL AND Telefon NOT IN ('') 
                 AND [E-mail] IS NOT NULL AND [E-mail] NOT IN ('')))
            ORDER BY 
                Vennenr

    OPEN Friend_Cursor
  
    FETCH NEXT FROM Friend_Cursor INTO @Vennenr, @shortenfornavn, @fornavn, @efternavn, @adresse, @postnr, @telefon, @tlf1, @email
    --loop på alle venner > 0

    WHILE @@FETCH_STATUS = 0 
    BEGIN
        -- Check om venner er håndteret før
        IF (SELECT COUNT(FriendID) FROM #tempTable WHERE FriendID = @Vennenr) = 0  
        BEGIN
            -- initializing
            SET @done = 0;
  
            -- Indsæt første dublet
            INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
            VALUES (@Vennenr, @dubletNo, 1, 1,1,1,1,1,1,1,1,0,0,1)

            SET @subDubletNo = 1;
 
            -- Første check 
            IF @done = 0 
            BEGIN
                IF EXISTS (SELECT Vennenr               
                           FROM Medlemsdata
                           LEFT OUTER JOIN Postnumre 
                           RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr 
                                 ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                           WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (ISNULL(telefon,'') LIKE '%' + @telefon + '%') AND (LEN(@telefon) > 7) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
            )
            BEGIN
                INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
                SELECT Vennenr, @dubletNo, ROW_NUMBER() OVER (ORDER BY Vennenr) + @subDubletNo, 0,0,0,0,0,0,0,0,0,0,0
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (ISNULL(telefon,'') LIKE '%' + @telefon + '%') AND (LEN(@telefon) > 7) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
                SET @subDubletNo = (SELECT COUNT(FriendID) FROM #tempTable WHERE DubletNo = @dubletNo)
                SET @done = 1
            END
        END
        -- Andet check
        IF @done = 0 BEGIN
            IF EXISTS (
                SELECT Vennenr
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn IN (@fornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
            )
            BEGIN
                INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
                SELECT Vennenr, @dubletNo, ROW_NUMBER() OVER (ORDER BY Vennenr) + @subDubletNo, 0,0,0,0,0,0,0,0,0,0,0
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn IN (@fornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
                SET @subDubletNo = (SELECT COUNT(FriendID) FROM #tempTable WHERE DubletNo = @dubletNo)
                SET @done = 1
            END
        END
        -- Tredje check
        IF @done = 0 BEGIN
            IF EXISTS (
                SELECT Vennenr
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (ISNULL(Tlf1,'') LIKE '%' + @tlf1 + '%') AND (LEN(@tlf1) > 7) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
            )
            BEGIN
                INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
                SELECT Vennenr, @dubletNo, ROW_NUMBER() OVER (ORDER BY Vennenr) + @subDubletNo, 0,0,0,0,0,0,0,0,0,0,0
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@Adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (ISNULL(Tlf1,'') LIKE '%' + @tlf1 + '%') AND (LEN(@tlf1) > 7) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
                SET @subDubletNo = (SELECT COUNT(FriendID) FROM #tempTable WHERE DubletNo = @dubletNo)
                SET @done = 1
            END
        END

        -- Fjerde check
        IF @done = 0 BEGIN
            IF EXISTS (
                SELECT Vennenr
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (Upper_Email IN (@email)) AND (Upper_Email NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
            )
            BEGIN
                INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
                SELECT Vennenr, @dubletNo, ROW_NUMBER() OVER (ORDER BY Vennenr) + @subDubletNo, 0,0,0,0,0,0,0,0,0,0,0
                FROM Medlemsdata
                LEFT OUTER JOIN Postnumre
                RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (Upper_Adresse IN (@adresse)) AND (Upper_Adresse NOT IN ('')) AND
                                                (Upper_Postnr IN (@postnr)) AND (Upper_postnr NOT IN ('')) AND
                                                (Upper_Email IN (@email)) AND (Upper_Email NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
                SET @subDubletNo = (SELECT COUNT(FriendID) FROM #tempTable WHERE DubletNo = @dubletNo)
                SET @done = 1
            END
        END
        -- Femte check
        IF @done = 0 BEGIN
            IF EXISTS (
                SELECT Vennenr
                FROM Medlemsdata
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (ISNULL(Telefon,'') LIKE '%' + @telefon + '%') AND (LEN(@telefon) > 7) AND
                                                (Upper_Email IN (@email)) AND (Upper_Email NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
            )
            BEGIN
                INSERT INTO #tempTable (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
                SELECT Vennenr, @dubletNo, ROW_NUMBER() OVER (ORDER BY Vennenr) + @subDubletNo, 0,0,0,0,0,0,0,0,0,0,0
                FROM Medlemsdata
                WHERE (Vennenr <> @Vennenr) AND (Upper_Fornavn_FirstPart IN (@shortenfornavn)) AND (Upper_Fornavn NOT IN ('')) AND
                                                (Upper_Efternavn IN (@efternavn)) AND (Upper_Efternavn NOT IN ('')) AND
                                                (ISNULL(Telefon,'') LIKE '%' + @telefon + '%') AND (LEN(@telefon) > 7) AND
                                                (Upper_Email IN (@email)) AND (Upper_Email NOT IN ('')) AND
                                                vennenr > 0 AND
                                                vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4) AND
                                                vennenr NOT IN (SELECT FriendID FROM #tempTable)
                SET @subDubletNo = (SELECT COUNT(FriendID) FROM #tempTable WHERE DubletNo = @dubletNo)
                SET @done = 1
            END
        END
        -- Hvis der ikke var noget match, så ...
        IF @subDubletNo = 1 BEGIN
            DELETE FROM #tempTable WHERE FriendID = @Vennenr
        END
        ELSE BEGIN
            SET @dubletNo = @dubletNo + 1
        END
    END
    FETCH NEXT FROM Friend_Cursor INTO @Vennenr, @shortenfornavn, @fornavn, @efternavn, @adresse, @postnr, @telefon, @tlf1, @email
END
INSERT INTO DuplicateList (FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate])
SELECT FriendID, DubletNo, SubDubletNo, [UseOrganisation], [UseFornavn], [UseEfternavn], [UseAdresse], [UsePostCode], [UseTlf1], [UseTlf2], [UseEmail], [Choice], [AKeep], [UseBornDate]
FROM #tempTable
CLOSE Friend_Cursor
DEALLOCATE Friend_Cursor

UPDATE DuplicateSetup SET IsOrdered = 0, OrderDateTime = null, UserID = @UserID, Updated = CURRENT_TIMESTAMP
INSERT INTO DuplicateTimeConsumption (ALevel, TimeConsumption) VALUES (4, current_Timestamp - @oldtime)

SET NOCOUNT OFF

ALTER TABLE Medlemsdata ADD Upper_Fornavn_FirstPart AS 

CASE
                    WHEN CHARINDEX(' ', Fornavn) = 0 THEN UPPER(Fornavn)
                    WHEN CHARINDEX(' ', Fornavn) > 0 THEN UPPER(RTRIM(LEFT(Fornavn,CHARINDEX(' ', Fornavn))))
                END
PERSISTED

我真的希望有/有绩效优化的基础，希望有人能给我一个想法，告诉我应该注意什么。 测试代码如下：

提前感谢,

---

Michael

但是我遇到了一个存储过程的问题，该存储过程需要将近2个小时才能执行。清除光标将是一个巨大的步骤。老实说，这看起来你把问题复杂化了。我想你最好从一开始就解释一下这里的目标是什么。另外，为什么要为上限值计算列？您的数据库是否在区分大小写的排序规则中？感谢您的写作，如果我必须查看游标问题，我有什么可能避免使用游标？之所以使用上柱，是因为无论大小写，我们都要搜索字符串。我们的目标是搜索重复记录。之所以使用上栏，是因为无论大小写，我们都要搜索字符串。我问你是否使用区分大小写的排序规则，这是一个含糊不清的肯定回答吗？如果不在区分大小写的排序规则中，则上面的计算列没有任何用途，因为“all in lowercase”=“all in lowercase”将返回True。@MichaelEriksen将所有内容重写为更新、插入、删除或选择查询。所有查询数据修改语句都可以处理来自带有eg INSERT的表或查询的数据。。从…中选择。。。具体在哪里？我没有时间。通常，不要考虑处理一行，而是考虑如何执行一组操作。您所做的大部分工作似乎都是过滤数据。找出如何将数据作为一个组进行筛选，而不是按行进行筛选。SQL是一种基于集合的语言。如果你那样使用它，效果最好。

SELECT Vennenr              
FROM Medlemsdata
LEFT OUTER JOIN Postnumre
RIGHT OUTER JOIN MedlemsAdresse ON Postnumre.Postnummer = MedlemsAdresse.Postnr ON Medlemsdata.FK_AdrID = MedlemsAdresse.AdrID
WHERE (Vennenr <> 1) AND Upper_Fornavn_FirstPart = CASE WHEN Upper_Fornavn_FirstPart IS NOT NULL THEN 'MICHAEL' ELSE '' END AND
Upper_Efternavn = CASE WHEN Upper_Efternavn IS NOT NULL THEN 'ERIKSEN' ELSE '' END AND
Upper_Adresse = CASE WHEN Upper_Adresse IS NOT NULL THEN 'HELIOSVEJ 23' ELSE '' END AND
Upper_Postnr = CASE WHEN Upper_Postnr IS NOT NULL THEN '7100' ELSE '' END AND (ISNULL(telefon,'') LIKE '%' + '23747585' + '%') AND (LEN('23747585') > 7) AND
vennenr > 0 AND
vennenr NOT IN (SELECT FriendID FROM DuplicateForgetFriends WHERE ALevelNo = 4)