SQL对当天的多个值求和

这是我的桌子

TIME                     Status
2012-11-15 8:30:00.000   "WAS_FLOW"
2012-11-15 9:00:00.000   "WAS_FLOW"
2012-11-15 10:30:00.000  "H2_FLOW"
2012-11-11 12:14:00.00   "O23HZ_FLOW"
2012-11-11 8:00.00.000   "AZ_FLOW"
2012-11-12 9:00.000      "BZ_FLOW"

我希望我的结果显示：

TIME         "WAS FLOW"    
2012-11-11   0
2012-11-12   0
2012-11-15   2

请尝试以下内容：

   SELECT DISTINCT  CONVERT(VARCHAR(10), a.TIME, 101),
          CASE b.COUNT WHEN NULL THEN 0 ELSE b.COUNT END AS "WAS FLOW"
   FROM MyTable AS a 
       LEFT JOIN 
            (SELECT Count(STATUS) AS "COUNT"
             FROM MyTable
             WHERE Status = 'WAS_FLOW'
             GROUP BY Time
            ) AS b
   ON a.TIME= b.TIME;

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这里的其他答案都有轻微的问题。这是一个我希望能直接为你工作的盒子

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演示

这不会包括结果为0的输出行，相反，这些行将不会显示。另外，我如何获取eaach的总和状态day@user1836442：更新了答案。如果没有帮助，请检查并让我知道。我想你需要说选择时间，将（状态）计数为“计数”2012-11-11 9:00.000 NULL 2012-11-12 8:00.00.000 NULL 2012-11-15 10:30:00.000 NULL 2012-11-15 12:14:00.00 NULL 2012-11-15 8:30:00.000 1 2012-11-15 9:00:00.000 1我得到这个错误“将nvarchar数据类型转换为datetime数据类型导致值超出范围”。为什么要将时间存储为字符串？我强烈建议将其存储为datetime数据类型。如果不能，则可以使用

LEFT（time，10）

而不是

DATEADD

计算。

SELECT
  DATEADD(DAY, DATEDIFF(DAY, 0, [time]), 0)             AS [date],
  SUM(CASE WHEN status = 'WAS_FLOW' THEN 1 ELSE 0 END)  AS [count]
FROM
  yourTable
GROUP BY
  DATEADD(DAY, DATEDIFF(DAY, 0, [time]), 0)

SELECT CAST(TIME AS date) AS TIME,
       COUNT(CASE WHEN Status = 'WAS_FLOW' THEN Status END) AS 'WAS_FLOW'
FROM dbo.your_table
GROUP BY CAST(TIME AS date)