Sql 如何在CognosReportStudio中创建每个重复值的不同计数?
这些是我目前的数据Sql 如何在CognosReportStudio中创建每个重复值的不同计数?,sql,cognos-10,Sql,Cognos 10,这些是我目前的数据 ACCOUNT NUMBER PRODUCT STATUS RANK DESIGN 1 530033 Wealth Services Closed 1 Manual 2 530033 Wealth Services Closed 2 Manual 3 530033 Wealth Services Closed 3 Manual
ACCOUNT NUMBER PRODUCT STATUS RANK DESIGN
1 530033 Wealth Services Closed 1 Manual
2 530033 Wealth Services Closed 2 Manual
3 530033 Wealth Services Closed 3 Manual
4 530033 Wealth Services Closed 4 Manual
5 534656 Initial Escrow Open 1 Manual
6 534656 Initial Escrow Open 2 Manual
7 535161 Markets Integrity Closed 1 Manual
8 538379 Prepaid Cards Closed 1 Manual
9 538379 Prepaid Cards Closed 2 Manual
10 538379 Prepaid Cards Closed 3 Manual
11 538379 Prepaid Cards Closed 4 Manual
12 538915 Uploaded Cards Open 1 Manual
13 538915 Uploaded Cards Open 2 Manual
14 538915 Uploaded Cards Open 3 Manual
我想创建一个列,唯一地计算每个重复的帐号。例如,账号530033出现了四次,我想把每一个530033都算一次,同样的,另一个账号534656出现了两次才算一次
我已经尝试过以下方法,但都没有成功
count(distinct(Account Number))
count(distinct(Account Number) for Account Number)
聚合列等于总计、计数或自动
我将使用这些数据创建一个交叉选项卡。我的交叉表给我的总数是14,因为它计算了所有重复的帐号。因为所有帐号都有十四行。但实际上只有5个账号(530033、534656、535161、538379和53891)
理想情况下应该是这样
TOTAL Open Closed
Wealth Services 1 1
Initial Escrow 1 1
Markets Integrity 1 1
Prepaid Cards 1 1
Uploaded Cards 1 1
TOTAL 5
我应该创建一个名为Unique count of account Number的新列吗?但是我如何单独计算帐号呢
我是否必须创建另一个具有唯一帐号的表,然后将这两个表进行内部联接?我相信您需要的表达式如下所示: 总计
COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT])
打开
CASE [STATUS]
WHEN 'Open' THEN COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT],[STATUS])
ELSE NULL
END
关闭
CASE [STATUS]
WHEN 'Closed' THEN COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT],[STATUS])
ELSE NULL
END
确保将每个数据项的聚合函数设置为“计算”,因为我们正在手动指定聚合和汇总。Hello Johnson。我使用了你提供和创建的逻辑,它工作了!再次感谢。
CASE [STATUS]
WHEN 'Closed' THEN COUNT(DISTINCT [ACCOUNT NUMBER] for [PRODUCT],[STATUS])
ELSE NULL
END