Sql 子查询返回的多行用作表达式，但仅在函数中使用

当我使用一个函数时，它会给出上面提到的错误，但当单独使用相同的代码时，它就可以正常工作。问题出在哪里

玩弄功能：

用清洁选择键拨弄：

样本数据：

create table report
(report_day date,
 tickets_no integer,
 tickets_stake numeric,
 promo_tickets_no integer,
 promo_tickets_stake numeric,
 group_id integer);
 
 insert into report
 values
 ('2020-07-20',12,569.6, 2, 44,1),
 ('2020-07-20',61,2000, 5, 260,2),
  ('2020-07-21',35,1244.2, 11, 250,1),
  ('2020-07-21',100,2500.5, 29, 575,2),
   ('2020-07-22',66,2511.8, 23, 670,1),
   ('2020-07-22',125,3358.2, 50, 990,2);

CREATE OR REPLACE FUNCTION report(arguments json)
  RETURNS json AS
$BODY$
     
DECLARE 
        
    dateFrom date;
    dateTo date;
        selectedType integer;
BEGIN 
        
    dateFrom := cast(arguments->>'dateFrom' as date);
    dateTo := cast(arguments->>'dateTo' as date);
    selectedType := cast(arguments->>'selectedType' as integer);

RETURN (
    WITH full_data as (
 with tickets as (
  select 
    report_day
  , sum(tickets_no) as tickets_no
  , sum(tickets_stake) as tickets_stake
  FROM report
  WHERE selectedType = 0
  AND report_day between dateFrom and dateTo
  GROUP BY 1)
  
, promo_tickets as (
  select 
    report_day
  , sum(promo_tickets_no) as promo_tickets_no
  , sum(promo_tickets_stake) as promo_tickets_stake
  FROM report
  WHERE selectedType = 1
  AND report_day between dateFrom and dateTo
  GROUP BY 1)
  
  select 
    t.report_day 
  , sum(coalesce(t.tickets_no,0) + coalesce(pt.promo_tickets_no,0)) as tickets_no                             
  , sum(coalesce(t.tickets_stake,0) + coalesce(pt.promo_tickets_stake,0)) as tickets_no
  FROM tickets t
  LEFT JOIN promo_tickets pt on t.report_day = pt.report_day                                    
   GROUP BY 1
   ORDER BY 1)
        
select row_to_json(full_data) from full_data
);

END;
$BODY$
  LANGUAGE plpgsql VOLATILE
  COST 100;
  
  select * from report(json_build_object('dateFrom', '2020-07-20', 'dateTo', '2020-07-22','selectedType', 0 ))

---

因为您试图从只应返回一行的函数中返回多行。在函数中再添加一个参数，最好是主键列（我想

tickets\u no

），例如

并将查询重写为

WITH full_data AS
 (WITH tickets AS
     (SELECT report_day,
            SUM(tickets_no) AS tickets_no,
            SUM(tickets_stake) AS tickets_stake
       FROM report
      WHERE selectedType = 0
        AND report_day BETWEEN dateFrom AND dateTo
        AND tickets_no = i_tickets_no
      GROUP BY 1),
    promo_tickets as
     (select report_day,
            SUM(promo_tickets_no) as promo_tickets_no,
            SUM(promo_tickets_stake) as promo_tickets_stake
       FROM report
      WHERE selectedType = 1
        AND report_day BETWEEN dateFrom AND dateTo
      GROUP BY 1)
    
    select t.report_day,
           SUM(COALESCE(t.tickets_no, 0) + COALESCE(pt.promo_tickets_no, 0)) AS tickets_no,
           SUM(COALESCE(t.tickets_stake, 0) +
               COALESCE(pt.promo_tickets_stake, 0)) AS tickets_no
      FROM tickets t
      LEFT JOIN promo_tickets pt
        ON t.report_day = pt.report_day
     GROUP BY 1
     ORDER BY 1)

并通过添加第二个参数调用

---

因为您试图从只应返回一行的函数中返回多行。在函数中再添加一个参数，最好是主键列（我想

tickets\u no

），例如

并将查询重写为

WITH full_data AS
 (WITH tickets AS
     (SELECT report_day,
            SUM(tickets_no) AS tickets_no,
            SUM(tickets_stake) AS tickets_stake
       FROM report
      WHERE selectedType = 0
        AND report_day BETWEEN dateFrom AND dateTo
        AND tickets_no = i_tickets_no
      GROUP BY 1),
    promo_tickets as
     (select report_day,
            SUM(promo_tickets_no) as promo_tickets_no,
            SUM(promo_tickets_stake) as promo_tickets_stake
       FROM report
      WHERE selectedType = 1
        AND report_day BETWEEN dateFrom AND dateTo
      GROUP BY 1)
    
    select t.report_day,
           SUM(COALESCE(t.tickets_no, 0) + COALESCE(pt.promo_tickets_no, 0)) AS tickets_no,
           SUM(COALESCE(t.tickets_stake, 0) +
               COALESCE(pt.promo_tickets_stake, 0)) AS tickets_no
      FROM tickets t
      LEFT JOIN promo_tickets pt
        ON t.report_day = pt.report_day
     GROUP BY 1
     ORDER BY 1)

并通过添加第二个参数调用

---

如果希望函数像查询一样返回报表对象数组，请更改此部分：

select row_to_json(full_data) from full_data

要将行聚合到数组中，请执行以下操作：

select json_agg(row_to_json(full_data)) from full_data

如果希望函数返回多行，则需要进行两项更改：

CREATE OR REPLACE FUNCTION report(arguments json)
  RETURNS table (row_to_json json) AS

对于

返回

：

RETURN QUERY (
    WITH full_data as (

---

更新

如果希望函数像查询一样返回报表对象数组，请更改此部分：

select row_to_json(full_data) from full_data

要将行聚合到数组中，请执行以下操作：

select json_agg(row_to_json(full_data)) from full_data

如果希望函数返回多行，则需要进行两项更改：

CREATE OR REPLACE FUNCTION report(arguments json)
  RETURNS table (row_to_json json) AS

对于

返回

：

RETURN QUERY (
    WITH full_data as (

---

更新的

是否可以返回多个json行？@sh4rkyy如果函数返回类型为json，则不能返回。请参阅我答案的更新。是否可以返回多个json行？@sh4rkyy如果函数返回类型为

json

，则不可以。请参阅更新我的答案。