SQL Server-创建数据透视的简单方法

是否有人知道一种简单的方法来创建此结果的轴心：

[0-1]  [1-2]  [2-3]  [3-4]
12      45      29    5

此结果是通过以下查询创建的：

 SELECT [0-1]   = SUM(CASE WHEN AGE >= 0 AND AGE <= 1 THEN 1 ELSE 0 END),
       [1-2]  = SUM(CASE WHEN AGE > 1 AND AGE <= 2 THEN 1 ELSE 0 END),
       [2-3] = SUM(CASE WHEN AGE > 2 AND AGE <= 3 THEN 1 ELSE 0 END)
    FROM dbo.Persons

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也欢迎链接到文章/博客。请推荐一种简单易用的解决方案。

这里有一种使用

交叉连接和聚合的方法：

select ages.minage, ages.maxage,
       sum(case when age > ages.minage and age <= ages.maxage then 1 else 0 end) as cnt
from dbo.Persons cross join
     (select -1 as minage, 1 as maxage union all
      select 1, 2 union all
      select 2, 3
     ) as ages
group by ages.minage, ages.maxage

选择ages.minage、ages.maxage、，
sum（age>ages.minage和age get错误时的情况）：“列'ages.minage'在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中。”
select ages.minage, ages.maxage,
       sum(case when age > ages.minage and age <= ages.maxage then 1 else 0 end) as cnt
from dbo.Persons cross join
     (select -1 as minage, 1 as maxage union all
      select 1, 2 union all
      select 2, 3
     ) as ages
group by ages.minage, ages.maxage