f元素基于属性类型？@ARZ，我想是这样的，但正如您在C.M.Sperberg McQueen的回答中所看到的，当使用不同的值时，顺序是不能保证的。我将发布一个更新，并给出一个更为“SQL”导向的答案，其中我不使用不同的值，而是使用一个（或两个）表变量。这

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f元素基于属性

类型
？@ARZ，我想是这样的，但正如您在C.M.Sperberg McQueen的回答中所看到的，当使用
不同的值时，顺序是不能保证的。我将发布一个更新，并给出一个更为“SQL”导向的答案，其中我不使用
不同的值，而是使用一个（或两个）表变量。这可能更一般，但我不确定属性是否总是按文档顺序出现，因此我选择了一个更一般的解决方案，您可以在其中定义顺序。我猜他会和我的解决方案有同样的问题：MSSQL不支持自定义函数。。。
<Root>
    <Word Type="pre1" Value="A" />
    <Word Type="pre1" Value="D" />

    <Word Type="base" Value="B" />

    <Word Type="post1" Value="C" />
    <Word Type="post1" Value="E" />
    <Word Type="post1" Value="F" />
</Root>

<Root>
    <Word Type="pre1" Value="A" />
    <Word Type="pre1" Value="D" />

    <Word Type="pre2" Value="G" />
    <Word Type="pre2" Value="H" />

    <Word Type="base" Value="B" />

    <Word Type="post1" Value="C" />
    <Word Type="post1" Value="E" />
    <Word Type="post1" Value="F" />
</Root>

for $pre  in //Word[@Type="pre1"]
for $base in //Word[@Type="base"]
for $post in //Word[@Type="post1"]
return concat($pre/@Value, $base/@Value, $post/@Value)

declare function local:call($prefix as xs:string) as xs:string* {
  local:recursion('', 
    for $value in distinct-values(//Word/@Type[starts-with(., $prefix)])
    order by $value
    return $value
  )
};

declare function local:recursion($strings as xs:string*, $attributes as xs:string*) as xs:string* {
  if (empty($attributes))
  then $strings
  else
    for $string in $strings
    for $append in //Word[@Type=$attributes[1]]
    return local:recursion(concat($string, $append/@Value), $attributes[position() != 1])
};

for $pre in local:call('pre')
for $base in local:call('base')
for $post in local:call('post')
return concat($pre, $base, $post)

declare function local:cartesian-product(
  $doc as element(),
  $types as xs:string*
) as xs:string* {

  (: If we have no $types left, we are done.
     Return the empty string. :)
  if (empty($types)) then 
     ''

  (: Otherwise, take the first value off the 
     sequence of types and return the Cartesian
     product of all Words with that type and
     the Cartesian product of all the remaining
     types. :)
  else
     let $t := $types[1],
         $rest := $types[position() > 1]
     for $val in $doc/Word[@Type = $t]/@Value
     for $suffix in 
         local:cartesian-product($doc,$rest)
     return concat($val, $suffix)
  };

let $doc := <Root>
    <Word Type="pre1" Value="A" />
    <Word Type="pre1" Value="D" />

    <Word Type="pre2" Value="G" />
    <Word Type="pre2" Value="H" />

    <Word Type="base" Value="B" />

    <Word Type="post1" Value="C" />
    <Word Type="post1" Value="E" />
    <Word Type="post1" Value="F" />
</Root>

let $types0 := ($doc/Word/@Type),
    $types  := $types0[index-of($types0,.)[1]]

return local:cartesian-product($doc, $types)