Sql 查询以了解每天数据的平均值
我想知道8月份每个日期数据数量的平均值 示例Sql 查询以了解每天数据的平均值,sql,tsql,Sql,Tsql,我想知道8月份每个日期数据数量的平均值 示例 31-08 - 2 registers 30-08 - 3 registers 我尝试了下面的查询,但没有成功 SELECT AVG(ROW_NUMBER() over (order by Chave_ID desc)), DATEPART(day, datahora) from San_Chave where DATEPART(month, datahora) = 8 group by DATEPART(day, datahora), Ch
31-08 - 2 registers
30-08 - 3 registers
我尝试了下面的查询,但没有成功
SELECT AVG(ROW_NUMBER() over (order by Chave_ID desc)), DATEPART(day, datahora)
from San_Chave
where DATEPART(month, datahora) = 8
group by DATEPART(day, datahora), Chave_ID
order by DATEPART(day, datahora) desc
数据时间是DateTime
类型和
Chave_Id是主键
,但数字的顺序不符合逻辑,因此我尝试使用行编号()
函数
有人能帮我吗
我想要的输出
MONTH DAY REGISTER
8 31 10
8 30 9
8 29 1
表格
MONTH DAY REGISTER
8 31 10
8 30 9
8 29 1
要进行查询,我认为只需要Chave\u Id
和DataHora
,Chave\u Id
将是寄存器的数量
CREATE TABLE [dbo].[San_Chave](
[Chave_Id] [int] IDENTITY(1,1) NOT NULL,
[Usuario_Id] [int] NULL,
[Credenciada_Id] [int] NULL,
[Usuario_Id_Responsavel] [int] NULL,
[DataHora] [datetime] NULL,
[Transacao] [int] NULL,
[Cliente_Id] [int] NULL,
[DataHoraPegou] [datetime] NULL,
[DataHoraDevolverPrevisao] [datetime] NULL,
[DataHoraEntregou] [datetime] NULL,
[HorasDevolucao] [int] NULL,
[NomeResponsavel] [varchar](130) NULL,
[CpfResponsavel] [varchar](20) NULL,
[RgResponsavel] [varchar](20) NULL,
[TelResponsavel] [varchar](15) NULL,
[Tel2Responsavel] [varchar](15) NULL,
[Endereco] [varchar](300) NULL,
[Devolvido] [bit] NULL,
[TextoDevolucao] [varchar](5000) NULL,
[De] [int] NULL,
CONSTRAINT [PK_San_Chave] PRIMARY KEY CLUSTERED
(
[Chave_Id] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
GO
在没有看到您的模式的情况下进行猜测:
select Year, Month, avg(Count) as DailyAvgPerMonth
from (
select DATEPART(year, datahora) as Year,
DATEPART(month, datahora) as Month,
count(*) as Count
from Save_Chave
group by DATEPART(year, datahora),
DATEPART(month, datahora),
DATEPART(day, datahora)
) a
group by Year, Month
我认为这样的东西会给出所需的输出
SELECT CAST(DataHora AS DATE) AS [Date],
COUNT(Chave_ID) AS [Entries]
FROM San_Chave
GROUP BY CAST(DataHora AS DATE)
ORDER BY [Date]
请提供示例数据和所需输出。您肯定只需要一个
计数而不是计数的平均值?我不理解您使用平均值。具体来说,平均值是多少?@GarethD我不知道,也许一个计数可以解决。8月份每月每天插入我的表San_Chave
的寄存器数请提供用于生成该输出的数据。