Sql 与客户和日期对应的结果

即使两个日期之间没有订单，我如何获得所有日期的订单

样本表

OrderID  | Date      | CusID
33942    | 6-21-2014 | 6005
34059    | 6-20-2014 | 4003
53333    | 6-23-2014 | 6005
59234    | 6-23-2014 | 4003

我怎么会有这个结果

CusID   | Date      | OrderID |
4003    | 6-20-2014 | 34059   | 
4003    | 6-21-2014 | null    | 
4003    | 6-22-2014 | null    | 
4003    | 6-23-2014 | 59234   | 
6005    | 6-20-2014 | null    | 
6005    | 6-21-2014 | 33942   | 
6005    | 6-22-2014 | null    | 
6005    | 6-23-2014 | 53333   | 

这就是我到目前为止所做的

我创建了一个日历表

CREATE TABLE #Calendar
(
    [CalendarDate] DATETIME
)

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @EndDate = GETDATE()
SET @StartDate = DATEADD(Year, -1, @EndDate)


WHILE @StartDate <= @EndDate
      BEGIN
             INSERT INTO #Calendar
             (
                   CalendarDate
             )
             SELECT
                   @StartDate

             SET @StartDate = DATEADD(dd, 1, @StartDate)
      END 

---

创建日期和客户的笛卡尔乘积，然后加入

with cte as 
(
    select caldate, custid
    from calendar, customers
)
select *
from cte
left join temp o 
on cte.custid = o.custid
and cast(caldate as date) = cast(orderdate as date)
where caldate between '20140620' and '20140623'

---

首先，你的日历表坏了。您正在使用日期时间戳，并捕获表中的当前时间戳。写正确的数据比以后处理好

为此，有两种修复方法，使用

DATE

格式或

convert

日期删除时间戳。我选择了后者

从这里，您可以缩小到被查询的天数，以及这些天的客户数，并生成这两个子集的交叉连接

DECLARE @ORDER TABLE (ORDERID INT, ordDATE DATETIME, CUSID INT)
INSERT INTO @ORDER (ORDERID, ordDATE, CUSID)
VALUES (33942,'6-21-2014', 6005), 
       (34059,'6-20-2014',4003), 
       (53333,'6-23-2014',6005), 
       (59234,'6-23-2014',4003)

declare @Calendar table ([CalendarDate] DATETIME)

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @EndDate = GETDATE()
SET @StartDate = DATEADD(Year, -1, @EndDate)

WHILE @StartDate <= @EndDate
      BEGIN
             INSERT INTO @Calendar
             (
                   CalendarDate
             )
             SELECT
                   CONVERT(DATETIME,FLOOR(CONVERT(FLOAT, @StartDate)))

             SET @StartDate = DATEADD(dd, 1, @StartDate)
      END 

; with dates as
(
   SELECT DISTINCT CalendarDate
   FROM @Calendar
   WHERE CalendarDate BETWEEN '2014-06-20' AND '2014-06-23'
),
orders as
(
    SELECT DISTINCT CUSID
    FROM @ORDER
    WHERE ordDATE BETWEEN '2014-06-20' AND '2014-06-23'
),
cp AS
(
    SELECT *
    FROM dates
    CROSS JOIN orders
)

SELECT cp.CUSID, cp.CalendarDate, O.ORDERID
FROM CP
LEFT OUTER JOIN @ORDER O 
   ON cp.CalendarDate = O.ordDATE 
   AND cp.CUSID = O.CUSID

DECLARE@ORDER表（ORDERID INT，ordDATE DATETIME，CUSID INT）
插入@ORDER（ORDERID、ordDATE、CUSID）
价值（33942，'6-21-2014'，6005），
(34059,'6-20-2014',4003), 
(53333,'6-23-2014',6005), 
(59234,'6-23-2014',4003)
声明@Calendar表（[CalendarDate]DATETIME）
声明@StartDate DATETIME
声明@EndDate-DATETIME
SET@EndDate=GETDATE（）
设置@StartDate=DATEADD（年份，-1，@EndDate）
而@StartDate
DECLARE @ORDER TABLE (ORDERID INT, ordDATE DATETIME, CUSID INT)
INSERT INTO @ORDER (ORDERID, ordDATE, CUSID)
VALUES (33942,'6-21-2014', 6005), 
       (34059,'6-20-2014',4003), 
       (53333,'6-23-2014',6005), 
       (59234,'6-23-2014',4003)

declare @Calendar table ([CalendarDate] DATETIME)

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @EndDate = GETDATE()
SET @StartDate = DATEADD(Year, -1, @EndDate)

WHILE @StartDate <= @EndDate
      BEGIN
             INSERT INTO @Calendar
             (
                   CalendarDate
             )
             SELECT
                   CONVERT(DATETIME,FLOOR(CONVERT(FLOAT, @StartDate)))

             SET @StartDate = DATEADD(dd, 1, @StartDate)
      END 

; with dates as
(
   SELECT DISTINCT CalendarDate
   FROM @Calendar
   WHERE CalendarDate BETWEEN '2014-06-20' AND '2014-06-23'
),
orders as
(
    SELECT DISTINCT CUSID
    FROM @ORDER
    WHERE ordDATE BETWEEN '2014-06-20' AND '2014-06-23'
),
cp AS
(
    SELECT *
    FROM dates
    CROSS JOIN orders
)

SELECT cp.CUSID, cp.CalendarDate, O.ORDERID
FROM CP
LEFT OUTER JOIN @ORDER O 
   ON cp.CalendarDate = O.ordDATE 
   AND cp.CUSID = O.CUSID