Impala SQL:合并日期重叠的行。存在且不支持递归CTE的位置
我正在尝试在Impala SQL的表中合并日期间隔重叠的行。然而,我发现解决这一问题的解决方案不受Impala支持,例如WHERE EXISTS和递归CTE 我将如何在Impala中为此编写查询Impala SQL:合并日期重叠的行。存在且不支持递归CTE的位置,sql,impala,hue,Sql,Impala,Hue,我正在尝试在Impala SQL的表中合并日期间隔重叠的行。然而,我发现解决这一问题的解决方案不受Impala支持,例如WHERE EXISTS和递归CTE 我将如何在Impala中为此编写查询 Table: @T ID StartDate EndDate 1 20170101 20170201 2 20170101 20170401 3 20170505 20170531 4 20170530
Table: @T
ID StartDate EndDate
1 20170101 20170201
2 20170101 20170401
3 20170505 20170531
4 20170530 20170531
5 20170530 20170831
6 20171001 20171005
7 20171101 20171225
8 20171105 20171110
Required Output:
StartDate EndDate
20170101 20170401
20170505 20170831
20171001 20171005
我试图实现的目标在Impala中不受支持的示例:
SELECT
s1.StartDate,
MIN(t1.EndDate) AS EndDate
FROM @T s1
INNER JOIN @T t1 ON s1.StartDate <= t1.EndDate
AND NOT EXISTS(SELECT * FROM @T t2
WHERE t1.EndDate >= t2.StartDate AND t1.EndDate < t2.EndDate)
WHERE NOT EXISTS(SELECT * FROM @T s2
WHERE s1.StartDate > s2.StartDate AND s1.StartDate <= s2.EndDate)
GROUP BY s1.StartDate
ORDER BY s1.StartDate
选择
s1.起始日期,
最小值(t1.EndDate)作为EndDate
从@ts1开始
s1.StartDate=t2.StartDate和t1.EndDate 如果s1.StartDate>s2.StartDate和s1.StartDate,请务必对日期使用ISO格式:YYYY-MM-dd这完全符合我的要求。非常感谢!你是最好的。救生员。
select min(StartDate) as StartDate
,max(EndDate) as EndDate
from (select StartDate,EndDate
,count (is_gap) over
(
order by StartDate,ID
) as range_id
from (select ID,StartDate,EndDate
,case
when max (EndDate) over
(
order by StartDate,ID
rows between unbounded preceding
and 1 preceding
) < StartDate
then true
end as is_gap
from t
) t
) t
group by range_id
order by StartDate
;
+------------+------------+
| startdate | enddate |
+------------+------------+
| 2017-01-01 | 2017-04-01 |
| 2017-05-05 | 2017-08-31 |
| 2017-10-01 | 2017-10-05 |
| 2017-11-01 | 2017-12-25 |
+------------+------------+