oraclesql上的条件和

我以以下方式获得数据：

ITEM  LOCATION  UNIT RETAIL  QUANTITY 
100     KS         10          -10
200     KS         20           30

我想要正数（数量>0）和负数（数量<0）之和

如何根据条件获取这些列的总和？

您可以使用

sum（CASE…）

：

选择项目、位置、，
求和（当数量大于0时，则数量为0结束）为正和，
总和（当数量小于0时，则数量为0结束）为负和
从你的桌子上
按项目、地点分组；

---

您可以将

最大值

和

最小值

与

求和

功能结合使用：

Oracle 11g R2架构设置：

CREATE TABLE table_name ( ITEM, LOCATION, QUANTITY ) AS
          SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -20 FROM DUAL
UNION ALL SELECT 100, 'KS',  10 FROM DUAL
UNION ALL SELECT 100, 'KS',   5 FROM DUAL
UNION ALL SELECT 200, 'KS',  10 FROM DUAL
UNION ALL SELECT 200, 'KS',  20 FROM DUAL
UNION ALL SELECT 200, 'KS',   5 FROM DUAL

SELECT item,
       location,
       SUM( GREATEST( quantity, 0 ) ) AS positive_quantities,
       SUM( LEAST( quantity, 0 ) )    AS negative_quantities
FROM   table_name
GROUP BY item, location

| ITEM | LOCATION | POSITIVE_QUANTITIES | NEGATIVE_QUANTITIES |
|------|----------|---------------------|---------------------|
|  100 |       KS |                  15 |                 -40 |
|  200 |       KS |                  35 |                   0 |

查询1：

CREATE TABLE table_name ( ITEM, LOCATION, QUANTITY ) AS
          SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -20 FROM DUAL
UNION ALL SELECT 100, 'KS',  10 FROM DUAL
UNION ALL SELECT 100, 'KS',   5 FROM DUAL
UNION ALL SELECT 200, 'KS',  10 FROM DUAL
UNION ALL SELECT 200, 'KS',  20 FROM DUAL
UNION ALL SELECT 200, 'KS',   5 FROM DUAL

SELECT item,
       location,
       SUM( GREATEST( quantity, 0 ) ) AS positive_quantities,
       SUM( LEAST( quantity, 0 ) )    AS negative_quantities
FROM   table_name
GROUP BY item, location

| ITEM | LOCATION | POSITIVE_QUANTITIES | NEGATIVE_QUANTITIES |
|------|----------|---------------------|---------------------|
|  100 |       KS |                  15 |                 -40 |
|  200 |       KS |                  35 |                   0 |

：

CREATE TABLE table_name ( ITEM, LOCATION, QUANTITY ) AS
          SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -10 FROM DUAL
UNION ALL SELECT 100, 'KS', -20 FROM DUAL
UNION ALL SELECT 100, 'KS',  10 FROM DUAL
UNION ALL SELECT 100, 'KS',   5 FROM DUAL
UNION ALL SELECT 200, 'KS',  10 FROM DUAL
UNION ALL SELECT 200, 'KS',  20 FROM DUAL
UNION ALL SELECT 200, 'KS',   5 FROM DUAL

SELECT item,
       location,
       SUM( GREATEST( quantity, 0 ) ) AS positive_quantities,
       SUM( LEAST( quantity, 0 ) )    AS negative_quantities
FROM   table_name
GROUP BY item, location

| ITEM | LOCATION | POSITIVE_QUANTITIES | NEGATIVE_QUANTITIES |
|------|----------|---------------------|---------------------|
|  100 |       KS |                  15 |                 -40 |
|  200 |       KS |                  35 |                   0 |

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我喜欢用

最大/最小值
隐藏
案例的想法：）你能将执行计划与我的解决方案进行比较吗？@lad2025毫不奇怪，它们都有相同的计划。如果你想分析他们，你可以看看他们是否有不同的表现（但我怀疑，因为他们做的完全一样）。最终归结到哪个更可读/更易于维护/更易于键入/等等。。。