Sql 如何根据两个查询的结果进行数学运算

我必须检查每个查询的结果

第一个问题：

SELECT  [xcv],  COUNT( * ) AS Total
  FROM [my_table]  
 GROUP BY [xcv]

第二个问题：

SELECT [xcv],  COUNT( * ) AS Total
      FROM [my_table]   
    WHERE=[result]='ok'
    GROUP BY [xcv]

我想做的是得到->[（第一次查询/第二次查询）*100]的值

我想要表格中每个[xcv]的结果

你知道我怎么做吗

谢谢大家

SELECT t1.[xcv], 
       (t1.total/t2.total)*100
  FROM (SELECT [xcv],  
               COUNT( * ) AS Total
          FROM [my_table]  
        GROUP BY 
               [xcv]
        ) t1 JOIN (
                   SELECT [xcv], 
                          COUNT( * ) AS Total
                     FROM [my_table]   
                    WHERE [result]='ok'
                    GROUP BY 
                          [xcv]
                   ) t2
                  ON t1.[xcv]=t2.[xcv]

我还从

WHERE=[result]='ok'

中删除了

=

符号-我认为您输入错误。

一个查询：

SELECT [xcv],
       (SUM(CASE 
                 WHEN [result] = 'ok' 
                      THEN 1 
                      ELSE 0 
                 END
           )/COUNT( * )
        ) * 100
  FROM [my_table]
GROUP BY [xcv]

---

谢谢，伙计，效果很好。我可以再添加一列，告诉我每个[xcv]在我的表中存在多少次吗？

t1。总计是该列。只需将其添加到主
选择