SQL-如何在查询中直接更新XML列
我有一个SQL-如何在查询中直接更新XML列,sql,sql-server,Sql,Sql Server,我有一个XML列,其中包含以下值: <Parameters> <Parameter lastweekran_start="2016-06-04 00:00:00" lastweekran_end="2016-06-10 23:59:59" /> </Parameters> 我需要通过将每个值增加1周来更新属性lastweekran\u start和lastweekran\u end 有没有关于如何在不创建新XML的
XML
列,其中包含以下值:
<Parameters>
<Parameter lastweekran_start="2016-06-04 00:00:00"
lastweekran_end="2016-06-10 23:59:59" />
</Parameters>
我需要通过将每个值增加1周来更新属性lastweekran\u start
和lastweekran\u end
有没有关于如何在不创建新XML的情况下实现这一点的线索?我发现了两种解决方案,它们都不是很优雅,但都很有效。
A) 使用T-sqlxmldml
declare @tbl table(id int, params xml)
insert @tbl values
(1,'<Parameters><Parameter lastweekran_start="2016-06-04 00:00:00" lastweekran_end="2016-06-10 23:59:59" /></Parameters>')
,(2,'<Parameters><Parameter lastweekran_start="2015-06-04 00:00:00" lastweekran_end="2015-06-10 23:59:59" /></Parameters>')
;with par as (--extract values and add 1 week
select id, dateadd(week,1,t.v.value('@lastweekran_start','datetime')) lastweekran_start ,
dateadd(week,1,t.v.value('@lastweekran_end','datetime')) lastweekran_end
from @tbl cross apply params.nodes('Parameters/Parameter') t(v)
)
update @tbl --and update using modify with replace value of
--1. lastweekran_start
set params.modify('replace value of (Parameters/Parameter/@lastweekran_start)[1]
with sql:column("lastweekran_start")')
--2. lastweekran_end
--set params.modify('replace value of (Parameters/Parameter/@lastweekran_end)[1]
-- with sql:column("lastweekran_end")')
from @tbl t inner join par on t.id=par.id
--The issue here is that replace value of allows single node at a time
--So the query must run twice for lastweekran_end
--Comment 1st set block and uncomment 2nd one
我发现了两种解决方案,它们都不是很优雅,但都很有效。
A) 使用T-sqlxmldml
declare @tbl table(id int, params xml)
insert @tbl values
(1,'<Parameters><Parameter lastweekran_start="2016-06-04 00:00:00" lastweekran_end="2016-06-10 23:59:59" /></Parameters>')
,(2,'<Parameters><Parameter lastweekran_start="2015-06-04 00:00:00" lastweekran_end="2015-06-10 23:59:59" /></Parameters>')
;with par as (--extract values and add 1 week
select id, dateadd(week,1,t.v.value('@lastweekran_start','datetime')) lastweekran_start ,
dateadd(week,1,t.v.value('@lastweekran_end','datetime')) lastweekran_end
from @tbl cross apply params.nodes('Parameters/Parameter') t(v)
)
update @tbl --and update using modify with replace value of
--1. lastweekran_start
set params.modify('replace value of (Parameters/Parameter/@lastweekran_start)[1]
with sql:column("lastweekran_start")')
--2. lastweekran_end
--set params.modify('replace value of (Parameters/Parameter/@lastweekran_end)[1]
-- with sql:column("lastweekran_end")')
from @tbl t inner join par on t.id=par.id
--The issue here is that replace value of allows single node at a time
--So the query must run twice for lastweekran_end
--Comment 1st set block and uncomment 2nd one
为了他们所有人?OPENXML是一种选择吗?还是仅仅通过XQUery?对所有人?OPENXML是一种选择吗?或者仅仅通过XQUery?你是一个勇敢的灵魂。有点创造性的荣誉。:)你是一个勇敢的人。有点创造性的荣誉。:)