Sql 如何从select*from添加行号并获取所有列
我想添加行号,从表中选择连接列。我要全部列,而不是某一列。我需要修改下面的一些代码,但我不知道如何修改。需要你的帮助吗Sql 如何从select*from添加行号并获取所有列,sql,sql-server,Sql,Sql Server,我想添加行号,从表中选择连接列。我要全部列,而不是某一列。我需要修改下面的一些代码,但我不知道如何修改。需要你的帮助吗 SELECT * FROM (SELECT ROW_NUMBER() OVER (ORDER BY SMSAuctionItemId DESC) AS row ,a.SMSAuctionItemId ,a.nopolisi ,b.MerkName ,c.SeriN
SELECT *
FROM (SELECT ROW_NUMBER() OVER (ORDER BY SMSAuctionItemId DESC) AS row
,a.SMSAuctionItemId
,a.nopolisi
,b.MerkName
,c.SeriName
,d.SilinderName
,e.TipeName
,a.warna
,f.SubTipeName
FROM SMS_AuctionItemView a
LEFT JOIN MsMerk b ON a.MerkId=b.MerkId
LEFT JOIN MsSeri c ON a.SeriId=c.SeriId
LEFT JOIN MsSilinder d ON a.SilinderId=d.SilinderId
LEFT JOIN MsTipe e ON a.TipeId=e.TipeId
LEFT JOIN MsSubTipe f ON a.SubTipeId = f.SubTipeId
where CreateUserId= '8119'
and a.CompanyId = 1
and f.SubTipeId=15) x
WHERE row > 0
and row <= 15
并检索所有列,但当我删除它时,只给我行号列。您可以选择下面不同表中的所有列
SELECT ROW_NUMBER() OVER (ORDER BY SMSAuctionItemId DESC) AS row
,a.*
,b.*
,c.*
,d.*
,e.*
,f.*
FROM SMS_AuctionItemView a
LEFT JOIN MsMerk b ON a.MerkId=b.MerkId
LEFT JOIN MsSeri c ON a.SeriId=c.SeriId
LEFT JOIN MsSilinder d ON a.SilinderId=d.SilinderId
LEFT JOIN MsTipe e ON a.TipeId=e.TipeId
LEFT JOIN MsSubTipe f ON a.SubTipeId = f.SubTipeId
where CreateUserId= '8119'
and a.CompanyId = 1
and f.SubTipeId=15
但当您将其作为子查询时,如果多个表的任何列名相同,则会抛出您在
MerkId
中已经得到的错误,因为该列已经存在于SMS\u AuctionItemView和MsMerk
这两个表中。因此,您必须对多个表中存在的相同列名使用别名请告诉我们您为什么需要删除列列表,因为我想不出任何合理的理由。你面临的错误或复杂性是什么?因为我需要所有的数据columns@mkRabbani如果删除所有列,则只显示行数列,以便于帮助您!你的代码正在运行。但是如果我想添加更多的参数,比如WHERE row>0和row@NelvanBalthazar,我已经说过,如果你想使用这个查询作为子查询,那么你必须在选择时使用别名。列名是指,我必须在选择权中一个接一个地提到所有的列?
SELECT ROW_NUMBER() OVER (ORDER BY SMSAuctionItemId DESC) AS row
,a.*
,b.*
,c.*
,d.*
,e.*
,f.*
FROM SMS_AuctionItemView a
LEFT JOIN MsMerk b ON a.MerkId=b.MerkId
LEFT JOIN MsSeri c ON a.SeriId=c.SeriId
LEFT JOIN MsSilinder d ON a.SilinderId=d.SilinderId
LEFT JOIN MsTipe e ON a.TipeId=e.TipeId
LEFT JOIN MsSubTipe f ON a.SubTipeId = f.SubTipeId
where CreateUserId= '8119'
and a.CompanyId = 1
and f.SubTipeId=15