如果在表中创建了新条目，则使用减法计算SQL总和

如果表格中有新条目，我会尝试用减法求总和

TotalPoints查询：

SELECT SUM(t.TotalUserActions) as Actions, sum(t.AllTotalPoints) as TotalPoints,
(select Name from CustomerTable where CustomerId=1) as Name from 
(
SELECT CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) 
      FROM RedeemPointsTable where CustomerId=1) 
      ELSE COUNT(CustomerTable.CustomerId) 
      END as TotalUserActions , CustomerTable.Name,
    CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) 
      FROM RedeemPointsTable where CustomerId=1)*Points
      ELSE SUM(LoayaltyPointsTable.Points) 
      END as AllTotalPoints 

FROM
     LoayaltyPointsTable
INNER JOIN
     LoyaltyDetailsTable
on LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
INNER  JOIN 
     CustomerTable 
on CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId

where CustomerTable.CustomerID =1
group by CustomerTable.Name,LoayaltyPointsTable.LoyaltyPointsId,
         LoayaltyPointsTable.Points,CustomerTable.CustomerId
) t

Actions  Totalpoints     Name
30       500             John

TotalPoints:
100                         //  (500-400)

Totalpoints查询输出：

SELECT SUM(t.TotalUserActions) as Actions, sum(t.AllTotalPoints) as TotalPoints,
(select Name from CustomerTable where CustomerId=1) as Name from 
(
SELECT CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) 
      FROM RedeemPointsTable where CustomerId=1) 
      ELSE COUNT(CustomerTable.CustomerId) 
      END as TotalUserActions , CustomerTable.Name,
    CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) 
      FROM RedeemPointsTable where CustomerId=1)*Points
      ELSE SUM(LoayaltyPointsTable.Points) 
      END as AllTotalPoints 

FROM
     LoayaltyPointsTable
INNER JOIN
     LoyaltyDetailsTable
on LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
INNER  JOIN 
     CustomerTable 
on CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId

where CustomerTable.CustomerID =1
group by CustomerTable.Name,LoayaltyPointsTable.LoyaltyPointsId,
         LoayaltyPointsTable.Points,CustomerTable.CustomerId
) t

Actions  Totalpoints     Name
30       500             John

TotalPoints:
100                         //  (500-400)

价格表

Priceid Title Discriptions Pricepoints
    1    abc    abc           400
    2    def    def           500

PriceClaimId CustomerId PriceId
1               1         22
2               2         23

价格索赔表

Priceid Title Discriptions Pricepoints
    1    abc    abc           400
    2    def    def           500

PriceClaimId CustomerId PriceId
1               1         22
2               2         23

使用上表，我试图减去TotalPoints–基于PriceClaimTable中的CustomerId和PriceId的Pricepoints 如果PriceClaimTable中没有基于Customerid的新条目，那么只显示Totalpoints而不进行减法

到目前为止，我试图找到价格点

select PriceTable.PricePoints from PriceTable  

inner join PriceClaimTable 
on PriceTable.PriceId = PriceClaimTable.PriceId

inner join CustomerTable 
on CustomerTable.CustomerId = PriceClaimTable.CustomerId 

where CustomerTable.CustomerId =1

group by PriceTable.PricePoints

这使我的输出为：

PricePoints
400

预期输出：

SELECT SUM(t.TotalUserActions) as Actions, sum(t.AllTotalPoints) as TotalPoints,
(select Name from CustomerTable where CustomerId=1) as Name from 
(
SELECT CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) 
      FROM RedeemPointsTable where CustomerId=1) 
      ELSE COUNT(CustomerTable.CustomerId) 
      END as TotalUserActions , CustomerTable.Name,
    CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) 
      FROM RedeemPointsTable where CustomerId=1)*Points
      ELSE SUM(LoayaltyPointsTable.Points) 
      END as AllTotalPoints 

FROM
     LoayaltyPointsTable
INNER JOIN
     LoyaltyDetailsTable
on LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
INNER  JOIN 
     CustomerTable 
on CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId

where CustomerTable.CustomerID =1
group by CustomerTable.Name,LoayaltyPointsTable.LoyaltyPointsId,
         LoayaltyPointsTable.Points,CustomerTable.CustomerId
) t

Actions  Totalpoints     Name
30       500             John

TotalPoints:
100                         //  (500-400)

如何在一次查询中减去结果并根据customerid计算总分和

其他表格结构：

SELECT SUM(t.TotalUserActions) as Actions, sum(t.AllTotalPoints) as TotalPoints,
(select Name from CustomerTable where CustomerId=1) as Name from 
(
SELECT CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) 
      FROM RedeemPointsTable where CustomerId=1) 
      ELSE COUNT(CustomerTable.CustomerId) 
      END as TotalUserActions , CustomerTable.Name,
    CASE 
      WHEN LoayaltyPointsTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) 
      FROM RedeemPointsTable where CustomerId=1)*Points
      ELSE SUM(LoayaltyPointsTable.Points) 
      END as AllTotalPoints 

FROM
     LoayaltyPointsTable
INNER JOIN
     LoyaltyDetailsTable
on LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
INNER  JOIN 
     CustomerTable 
on CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId

where CustomerTable.CustomerID =1
group by CustomerTable.Name,LoayaltyPointsTable.LoyaltyPointsId,
         LoayaltyPointsTable.Points,CustomerTable.CustomerId
) t

Actions  Totalpoints     Name
30       500             John

TotalPoints:
100                         //  (500-400)

---

任何帮助都会很好。

基于SQL Fiddle，我做了一个新的尝试，我相信这是正确的，尽管John返回81而不是100：

;  with LP (CustomerId, Name, UserActions, TotalPoints) as (
SELECT
   C.CustomerId,
   C.Name,
   sum(case when P.LoyaltyPointsId = 4 then isnull(R.RedeemCount, 0) else 1 end),
   sum(P.Points * case when P.LoyaltyPointsId = 4 then isnull(R.RedeemAmount,0) else 1 end)
from
   CustomerTable C
   join LoyaltyDetailsTable D on D.CustomerId = C.CustomerId
   join LoyaltyPointTable P on P.LoyaltyPointsId = D.LoyaltyPointsId
   outer apply (
       select sum(Amount) as RedeemAmount, count(Amount) as RedeemCount 
       from RedeemPointsTable R
       where R.CustomerId = C.CustomerId
   ) R
   group by C.CustomerId, C.Name
),

PP (CustomerId, Pricepoints) as (
    select C.CustomerId, sum(P.Pricepoints)
    from PriceTable P
    join PriceClaimTable C on P.PriceClaimId = C.PriceClaimId
    group by C.CustomerId
)

select 
    LP.CustomerId, LP.Name, LP.UserActions, LP.TotalPoints - isnull(PP.Pricepoints, 0) as Points
from
    LP
    left outer join PP on LP.CustomerId = PP.CustomerId 
order by LP.CustomerId

假设客户总是从忠诚度表中找到，但不必从兑换表或价格表中找到

---

此版本的SQL FIDLE:

是否可以将这两个查询都设置为CTE，然后合并结果？您需要将这些列添加到连接所需的select子句中。@JamesZ，您能举个例子吗？我已经用PriceTable结构和SQLFIDLE中的其他表更新了文章，看一看，可能会对您有所帮助，到时候我将使用CTEhi尝试您的查询谢谢您的努力，我正在尝试使用where customer id=1查找，检查是否有清晰的视图。当然，您可以在那里添加customer id=1的条件，然后它将只返回第一行。顺便问一下，我们是否真的有意让来自RedemptionStable的数据计算两次，因为在LoyaltyDetailsTable中有两条记录。也许你错过了一个日期？嗨，正如你说的检查，我不能在中使用客户id，你能不能编辑我尝试过的那些，但你的SQL太混乱了，我无法理解或修复，这就是为什么我写了我自己的。。。根据表格，我仍然认为这是正确的（除了稳定，这没有意义…）