SQL如何将行转换为列，将列转换为行？db2

我有一个SQL查询，它在DB2中运行良好 我的结果是

SERVICE   IN   OUT   INPROGRESS

ADSL      1     5      10
VOIP      15    12     11
IPTV      20    14     17

现在我想把它变成这样：

CLASS       ADSL   VOIP   IPTV

IN           1     5      10
OUT          15    12     11
INPROGRESS   20    14     17

虽然它看起来很长，但我的SQL非常简单，但我从未改变过这一点。如果有人知道我会心存感激

我的SQL是

select  distinct 'ADSL' as SERVICE,

(select count(*) as In from ticket 
where 
(class='C1'  and
(servicesinfault='25'))),

(select count(*) as Out from ticket
where 
(class='C2' and
(servicesinfault='25'))),


(select count(*) as In_progress from ticket
where 
(class='C3' and
(servicesinfault='25')))

from ticket where servicesinfault = '25'

union all

select  distinct 'VoIP',

(select count(*) from ticket 
where
(class='C1'  and
(servicesinfault='26'))),

(select count(*) from ticket
where
(class='C2'  and
(servicesinfault='26'))),


(select count(*) from ticket
where 
(class='C3'  and
(servicesinfault='26')))

from ticket where servicesinfault = '26'

union all

select  distinct 'IPTV',

(select count(*) from ticket 

where 
(class='C1'  and
(ticket.servicesinfault='27'))),

(select count(*) from ticket
where 
(class='C2'  and
(servicesinfault='27'))),

(select count(*) from ticket
where 
(class='C3'  and
(servicesinfault='27')))

from ticket where servicesinfault = '27'

---

你要找的词是“支点”

如果您的DBMS不提供，您可以使用“穷人的轴心”

看看usr对这个问题的回答：

---

作为备注，您的结果应该是：

CLASS       ADSL   VOIP   IPTV

IN           1     15     20
OUT          5     12     14
INPROGRESS   10    11     17

枢轴版本应类似于：

select distinct 'In' as CLASS,

                (select count(*) as 'ADSL'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '25'))),

                (select count(*) as 'VoIP'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '26'))),

                (select count(*) as 'IPTV'
                   from ticket
                  where (class = 'C1' and (servicesinfault = '27')))

  from ticket
 where class = 'C1'

union all

select distinct 'Out',

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '25'))),

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '26'))),

                (select count(*)
                   from ticket
                  where (class = 'C2' and (servicesinfault = '27')))

  from ticket
 where class = 'C2'

union all

select distinct 'InProgress',

                (select count(*)
                   from ticket

                  where (class = 'C3' and (ticket.servicesinfault = '25'))),

                (select count(*)
                   from ticket
                  where (class = 'C3' and (servicesinfault = '26'))),

                (select count(*)
                   from ticket
                  where (class = 'C3' and (servicesinfault = '27')))

  from ticket
 where class = 'C3'

---

哪些RBDM（SQL Server、Oracle、Mysql等）？对于大多数人来说，这个问题有很多重复之处。据我所知，没有一个DB2 Pivot等价物，我建议采用下面Ben回答中链接中建议的方法。@Dejan看看这个链接，它提供了一种不使用

Pivot

的方法。他在你澄清你使用的是哪种RBDM之前发布了；-）@Dejan，不是我上次检查的，但最新版本可能是。