如何通过SQL语句逐日显示DB2中最近5天的审计记录，并在一行中逐日显示这些记录的计数

对于管理员，我正在执行某种类型的sql操作。记录的类型如下

date        number of failed login
13/02/2017            1
12/02/2017            2
11/02/2017            0
10/02/2017            9
09/02/2017            0

我希望0,9,0,2,1在一行中

我尝试了下面的查询。但默认情况下无法获取零。 用户执行零操作的用户日必须在那里

select LISTAGG(cnt, ', ') 
from (select count(*) as cnt 
      from OPERATIONINFO 
      where OPERATIONTYPE='FAILEDLOGIN' 
        and CUSTID = 123 
        and date(UPDATEDDATEOFLOGIN) > (current date - 5 day)  
      group by YEAR(date), MONTH(date), DAY(date) 

---

请提供帮助。

您需要使用解码来透视数据。看看这个例子

INSERT INTO Sales VALUES
(2004, 1, 20),
(2004, 2, 30),
(2004, 3, 15),
(2004, 4, 10),
(2005, 1, 18),
(2005, 2, 40),
(2005, 3, 12),
(2005, 4, 27);

对此

Year Q1 Q2 Q3 Q4
---- -- -- -- --
2004 20 30 15 10
2005 18 40 12 27

---

你需要一张日期表。。。在这里，我使用递归进行动态生成-这不是最好的方法

WITH DATES_TABLE AS 
(
   SELECT CURRENT DATE - 5 DAYS AS D FROM SYSIBM.SYSDUMMY1

   UNION ALL

   SELECT D + 1 DAY AS D FROM DATES_TABLE WHERE D < CURRENT DATE
), THE_DATA AS
(
  select D.D, SUM(CASE WHEN O.UPDATEDDATEOFLOGIN IS NOT NULL THEN 1 ELSE 0 END) as cnt 
  from DATES_TABLE D
  LEFT JOIN OPERATIONINFO O ON O.UPDATEDDATEOFLOGIN = D.D
  where O.OPERATIONTYPE='FAILEDLOGIN' 
    and O.CUSTID = 123 
  group by D.D

)
select  LISTAGG(cnt, ', ') 
from THE_DATA

---

默认情况下我想要零。这只会在用户执行任何操作的情况下获取记录。我对代码进行了格式化，以使其可读，并且很明显您缺少一个-它去哪里了？在分组之前？谢谢在分组之前我错过了括号。。

WITH DATES_TABLE AS 
(
   SELECT CURRENT DATE - 5 DAYS AS D FROM SYSIBM.SYSDUMMY1

   UNION ALL

   SELECT D + 1 DAY AS D FROM DATES_TABLE WHERE D < CURRENT DATE
), THE_DATA AS
(
  select D.D, SUM(CASE WHEN O.UPDATEDDATEOFLOGIN IS NOT NULL THEN 1 ELSE 0 END) as cnt 
  from DATES_TABLE D
  LEFT JOIN OPERATIONINFO O ON O.UPDATEDDATEOFLOGIN = D.D
  where O.OPERATIONTYPE='FAILEDLOGIN' 
    and O.CUSTID = 123 
  group by D.D

)
select  LISTAGG(cnt, ', ') 
from THE_DATA