Sql 检查两行之间是否存在差异
我有下表:Sql 检查两行之间是否存在差异,sql,sql-server,sql-server-2008,tsql,compare,Sql,Sql Server,Sql Server 2008,Tsql,Compare,我有下表: column_a column_b column_c column_d column_date 1 test_1 test_1 type_1 11:00 2 test_2 test_2 type_2 11:01 3 test_3 test_6 type_2 11:02 4 test_4 test_4 type_3 11:03 5 test_2 test_6 t
column_a column_b column_c column_d column_date
1 test_1 test_1 type_1 11:00
2 test_2 test_2 type_2 11:01
3 test_3 test_6 type_2 11:02
4 test_4 test_4 type_3 11:03
5 test_2 test_6 type_2 11:04
6 test_1 test_2 type_1 11:05
我必须检查哪一行在列_b和列_c中有另一个值,该值由列_d类型过滤。对于每种类型,我必须仅使用sql脚本分析按列\u date排序的前两行。
如果列_b、列_c或列_d中的两行之间存在差异,我必须打印出第一行的值,否则为空
在上面的示例中,我期望得到以下结果:
column_a column_b column_c column_d column_date
5 test_2 null type_2 11:04
6 null test_2 type_1 11:05
我可以使用MS SQL Server 2008的T-SQL。我不清楚您在列_date列中使用的数据类型,但让我们假设它是时间1
嗨Dalex,非常感谢!就这样-
DECLARE @Table TABLE (
column_a INT ,
column_b VARCHAR (128),
column_c VARCHAR (128),
column_d VARCHAR (128),
column_date [time] );
INSERT INTO @Table
VALUES
('1', 'test_1', 'test_1', 'type_1', '11:00'),
('2', 'test_2', 'test_2', 'type_2', '11:01'),
('3', 'test_3', 'test_6', 'type_2', '11:02'),
('4', 'test_4', 'test_4', 'type_3', '11:03'),
('5', 'test_2', 'test_6', 'type_2', '11:04'),
('6', 'test_1', 'test_2', 'type_1', '11:05');
WITH C
AS (SELECT *,
ROW_NUMBER() OVER (PARTITION BY column_d ORDER BY column_date DESC) AS RN
FROM @Table),
ToCompare
AS (SELECT *
FROM c
WHERE Rn < 3
AND EXISTS (SELECT *
FROM c AS C2
WHERE C.column_d = C2.column_d
AND Rn = 2))
SELECT T.column_a,
NULLIF (T.column_b, T2.column_b) AS [column_b],
NULLIF (T.column_c, T2.column_c) AS [column_c],
T.column_d,
T.column_date
FROM ToCompare AS T
INNER JOIN
ToCompare AS T2
ON T.column_d = T2.column_d
WHERE T.Rn = 1
AND T2.RN = 2
ORDER BY T.column_a;