SQL Server-获取多对多关系中一行的所有子项？

我试图在SQLServer中编写一个递归查询，它基本上列出了给定父对象的父子层次结构。一个父级可以有多个子级，并且一个子级可以属于多个父级，因此它存储在多对多关系中

我从另一个有点相关的问题修改了下面的查询，但是这不会一直到树，只选择第一级子级

DECLARE @ObjectId uniqueidentifier
SET @ObjectId = '1A213431-F83D-49E3-B5E2-42AA6EB419F1';

WITH Tree AS
(
   SELECT A.*
   FROM Objects_In_Objects A
   WHERE A.ParentObjectId = @ObjectId

   UNION ALL

   SELECT B.*
   FROM Tree A
   JOIN Objects_In_Objects B
   ON A.ParentObjectId = B.ObjectId
)
SELECT *
FROM Tree
INNER JOIN Objects ar on tree.ObjectId = ar.ObjectId

是否有人知道如何修改查询，使其一直向下进入“树”？或者使用上述结构不可能实现这一点

对象

列：

ObjectId

|

Name

对象中的对象

列：

ObjectId

|

ParentObjectId

样本数据：

物体

对象中的对象

这个能帮你吗

这样一个递归CTE（公共表表达式）将一直有效

试试这个：

;WITH Tree AS
(
   SELECT A.ObjectID, A.ObjectName, o.ParentObjectID, 1 AS 'Level'
   FROM dbo.Objects A
   INNER JOIN dbo.Objects_In_Objects o ON A.ObjectID = o.ParentObjectID
   WHERE A.ObjectId = @ObjectId           -- use the A.ObjectId here

   UNION ALL

   SELECT A2.ObjectID, A2.ObjectName, B.ParentObjectID, t.Level + 1 AS 'Level'
   FROM Tree t 
   INNER JOIN dbo.Objects_In_Objects B ON B.ParentObjectID = t.ObjectID
   INNER JOIN dbo.Objects A2 ON A2.ObjectId = B.ObjectId        
)
SELECT *
FROM Tree
INNER JOIN dbo.Objects ar on tree.ObjectId = ar.ObjectId

如果你改变这一点-这对你现在有用吗？（我添加了一个

Level

列-通常有助于理解每行层次结构中的“深度”）

我似乎在我的SQL Server实例上获得了正确的输出，至少

declare @Objects_In_Objects table
(
  ObjectID uniqueidentifier, 
  ParentObjectId uniqueidentifier
)

declare @Objects table
(
  ObjectId uniqueidentifier, 
  Name varchar(50)
)

insert into @Objects values
('1A213431-F83D-49E3-B5E2-42AA6EB419F1', 'Main container'),  
('63BD908B-54B7-4D62-BE13-B888277B7365', 'Sub container'),  
('71526E15-F713-4F03-B707-3F5529D6B25E', 'Sub container 2'),  
('ADA9A487-7256-46AD-8574-0CE9475315E4', 'Object in multiple containers')

insert into @Objects_In_Objects values
('ADA9A487-7256-46AD-8574-0CE9475315E4', '71526E15-F713-4F03-B707-3F5529D6B25E'),
('ADA9A487-7256-46AD-8574-0CE9475315E4', '63BD908B-54B7-4D62-BE13-B888277B7365'),
('63BD908B-54B7-4D62-BE13-B888277B7365', '1A213431-F83D-49E3-B5E2-42AA6EB419F1'),
('71526E15-F713-4F03-B707-3F5529D6B25E', '1A213431-F83D-49E3-B5E2-42AA6EB419F1')


DECLARE @ObjectId uniqueidentifier
SET @ObjectId = '1A213431-F83D-49E3-B5E2-42AA6EB419F1';

WITH Tree AS
(
   SELECT A.ObjectID,
          A.ParentObjectId
   FROM @Objects_In_Objects A
   WHERE A.ParentObjectId = @ObjectId

   UNION ALL

   SELECT B.ObjectID,
          B.ParentObjectId
   FROM Tree A
   JOIN @Objects_In_Objects B
   ON B.ParentObjectId = A.ObjectId
)
SELECT *
FROM Tree
INNER JOIN @Objects ar on tree.ObjectId = ar.ObjectId;

---

这就是你要找的吗

不，实际上这根本没有结果：）@ReFocus:更新了我的回答，我被你的各种表格搞混了：-）尝试了这个-似乎产生了我预期的输出…这与我的情况不同。。在我的情况下，注释属于单个实体，而注释可以属于多个实体。

;WITH Tree AS
(
   SELECT A.ObjectID, A.ObjectName, o.ParentObjectID, 1 AS 'Level'
   FROM dbo.Objects A
   INNER JOIN dbo.Objects_In_Objects o ON A.ObjectID = o.ParentObjectID
   WHERE A.ObjectId = @ObjectId           -- use the A.ObjectId here

   UNION ALL

   SELECT A2.ObjectID, A2.ObjectName, B.ParentObjectID, t.Level + 1 AS 'Level'
   FROM Tree t 
   INNER JOIN dbo.Objects_In_Objects B ON B.ParentObjectID = t.ObjectID
   INNER JOIN dbo.Objects A2 ON A2.ObjectId = B.ObjectId        
)
SELECT *
FROM Tree
INNER JOIN dbo.Objects ar on tree.ObjectId = ar.ObjectId

declare @Objects_In_Objects table
(
  ObjectID uniqueidentifier, 
  ParentObjectId uniqueidentifier
)

declare @Objects table
(
  ObjectId uniqueidentifier, 
  Name varchar(50)
)

insert into @Objects values
('1A213431-F83D-49E3-B5E2-42AA6EB419F1', 'Main container'),  
('63BD908B-54B7-4D62-BE13-B888277B7365', 'Sub container'),  
('71526E15-F713-4F03-B707-3F5529D6B25E', 'Sub container 2'),  
('ADA9A487-7256-46AD-8574-0CE9475315E4', 'Object in multiple containers')

insert into @Objects_In_Objects values
('ADA9A487-7256-46AD-8574-0CE9475315E4', '71526E15-F713-4F03-B707-3F5529D6B25E'),
('ADA9A487-7256-46AD-8574-0CE9475315E4', '63BD908B-54B7-4D62-BE13-B888277B7365'),
('63BD908B-54B7-4D62-BE13-B888277B7365', '1A213431-F83D-49E3-B5E2-42AA6EB419F1'),
('71526E15-F713-4F03-B707-3F5529D6B25E', '1A213431-F83D-49E3-B5E2-42AA6EB419F1')


DECLARE @ObjectId uniqueidentifier
SET @ObjectId = '1A213431-F83D-49E3-B5E2-42AA6EB419F1';

WITH Tree AS
(
   SELECT A.ObjectID,
          A.ParentObjectId
   FROM @Objects_In_Objects A
   WHERE A.ParentObjectId = @ObjectId

   UNION ALL

   SELECT B.ObjectID,
          B.ParentObjectId
   FROM Tree A
   JOIN @Objects_In_Objects B
   ON B.ParentObjectId = A.ObjectId
)
SELECT *
FROM Tree
INNER JOIN @Objects ar on tree.ObjectId = ar.ObjectId;