提供重复值的Transact-SQL Select查询

首先，谢谢你花时间看这个

我试图从3个表中收集数据，并制作一个参考图表，允许最终用户查看存储的数据

对于本例，我基本上有3个表： 用户：

技能类型：

SKILL_PK    SKILL_NAME
11  Point of Sale
22  Digital Sales
33  Customer Service
44  Specialist Support

技能协会：

SKILL_ASSOC_PK  SKILL_PK    USER_PK START_DATE  STOP_DATE   Priority
99  11  1   36526   500000  2
88  11  2   36527   500000  3
77  22  1   36526   500000  3
66  33  3   36528   500000  1
55  44  4   36525   500000  1
444 33  4   36525   500000  4

（我知道我在SQL Express中对这些数据进行编目时可能违反了一些规则，但这只是一个示例，不能代表我正在使用的真实数据）

我的Select查询为每个用户返回多行不需要的结果： 声明：

 SELECT USERS.[USER_NAME], USERS.[USER_ID], 
    (CASE WHEN ST.SKILL_NAME ='Point of Sale' Then  SA.[PRIORITY] END) AS 'POS', 

    (CASE WHEN ST.SKILL_NAME ='Digital Sales' Then  SA.[PRIORITY] END) AS 'DS',
    (CASE WHEN ST.SKILL_NAME ='Customer Service' Then  SA.[PRIORITY] END) AS 'CS',
    (CASE WHEN ST.SKILL_NAME ='Specialist Support' Then  SA.[PRIORITY] END) AS 'Spec'
    FROM USERS
    INNER JOIN [dbo].[SKILL_ASSOCIATION] AS SA ON SA.USER_PK = USERS.USER_PK
    INNER JOIN SKILL_TYPE AS ST ON ST.SKILL_PK = SA.SKILL_PK

结果:

USER_NAME   USER_ID POS DS  CS  Spec
Bob 10000       2   NULL    NULL    NULL
Sally   10001       3   NULL    NULL    NULL
Bob 10000       NULL    3   NULL    NULL
Joe 10003       NULL    NULL    1   NULL
Susan   10004       NULL    NULL    NULL    1
Susan   10004       NULL    NULL    4   NULL

我也尝试过使用distinct，结果类似。 预期结果：

NAME    ID  POS DS  CS  Spec
Bob     1   2   3       
Sally   2   3           
Joe                 1
Susan               4   1

我使用此SQL Server的查询访问权限非常有限，无法从中创建/修改或删除以实现我的目标

任何指导都将不胜感激

谢谢，

---

Steven

您的预期输出意味着，按用户进行聚合，同时获取每个

案例

表达式的

MAX

，应该可以：

SELECT
    u.[USER_NAME],
    u.[USER_ID], 
    MAX(CASE WHEN ST.SKILL_NAME = 'Point of Sale' THEN SA.[PRIORITY] END) AS POS, 
    MAX(CASE WHEN ST.SKILL_NAME = 'Digital Sales' THEN SA.[PRIORITY] END) AS DS,
    MAX(CASE WHEN ST.SKILL_NAME = 'Customer Service' THEN SA.[PRIORITY] END) AS CS,
    MAX(CASE WHEN ST.SKILL_NAME = 'Specialist Support' THEN SA.[PRIORITY] END) AS Spec
FROM USERS u
INNER JOIN [dbo].[SKILL_ASSOCIATION] AS SA
    ON SA.USER_PK = u.USER_PK
INNER JOIN SKILL_TYPE AS ST
    ON ST.SKILL_PK = SA.SKILL_PK
GROUP BY
    u.[USER_NAME],
    u.[USER_ID];

---

谢谢你Yogesh Sharma！搞不清楚格式。天哪，太快了！这正是我想要的，非常感谢！一旦计时器用完，我将标记为已接受。

SELECT
    u.[USER_NAME],
    u.[USER_ID], 
    MAX(CASE WHEN ST.SKILL_NAME = 'Point of Sale' THEN SA.[PRIORITY] END) AS POS, 
    MAX(CASE WHEN ST.SKILL_NAME = 'Digital Sales' THEN SA.[PRIORITY] END) AS DS,
    MAX(CASE WHEN ST.SKILL_NAME = 'Customer Service' THEN SA.[PRIORITY] END) AS CS,
    MAX(CASE WHEN ST.SKILL_NAME = 'Specialist Support' THEN SA.[PRIORITY] END) AS Spec
FROM USERS u
INNER JOIN [dbo].[SKILL_ASSOCIATION] AS SA
    ON SA.USER_PK = u.USER_PK
INNER JOIN SKILL_TYPE AS ST
    ON ST.SKILL_PK = SA.SKILL_PK
GROUP BY
    u.[USER_NAME],
    u.[USER_ID];