Sql 显示请求的计数结果，水平显示作业结果，垂直显示位置3个表

因此，我有一个主数据表，它保存作业和位置的ID，例如：

请求表dbo.Requests

作业表dbo.Jobs

位置表dbo.Locations

现在我要做的是显示已完成作业和位置的计数列表，如：

Job Title      Total Jobs    Location 1   Location 2  Location 3
Job 1          30            5            15          10
Job 2          10            2            2           6
Job 3          40            22           0           18

第一部分显示作业和总计数很好，但我无法将要列出的位置放在右边

SELECT 
 job.JobTitle
,isnull(COUNT(req.JobID),0) AS 'Total Jobs'

FROM  Requests req 

RIGHT OUTER JOIN Jobs job
ON req.JobID = job.JobID

GROUP BY job.JobTitle
ORDER BY JobTitle

---

非常感谢

您可以使用以下查询

SELECT JobID,JobTitle,[1],[2],[3],[4],[5],[6],[7],[8]
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN([1],[2],[3],[4],[5],[6],[7],[8])) p

如果您想使用动态列数，您可以生成脚本并使用EXEC执行它

DECLARE @locationIDs varchar(200)=''

SELECT @locationIDs+=CONCAT(',[',LocationID,']')
FROM Locations
ORDER BY LocationID

SET @locationIDs=STUFF(@locationIDs,1,1,'')

--PRINT @locationIDs

DECLARE @query varchar(1000)=CONCAT('SELECT JobID,JobTitle,',@locationIDs,'
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN(',@locationIDs,')) p')

--PRINT @query

EXEC(@query)

带有位置标题的变体

DECLARE
  @locationIDs varchar(200)='',
  @locationTitles varchar(2000)=''

SELECT
  @locationIDs+=CONCAT(',[',LocationID,']'),
  @locationTitles+=CONCAT(',[',LocationID,'] [',LocationName,']')
FROM Locations
ORDER BY LocationID

SET @locationIDs=STUFF(@locationIDs,1,1,'')
SET @locationTitles=STUFF(@locationTitles,1,1,'')

--PRINT @locationIDs
--PRINT @locationTitles

DECLARE @query varchar(2000)=CONCAT('SELECT JobID,JobTitle,',@locationTitles,'
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN(',@locationIDs,')) p')

--PRINT @query

EXEC(@query)

---

有多少个地点？只有3个？还是未知？未知，因为它们将被添加和删除。谢谢，谢谢，快到了，它列出了右边一个区域的所有计数，但是它将ID列为标题而不是位置名称？@slowlygettingthere-如果SQLServer版本支持，您也可以在DECLARE块中使用varcharMAX类型。@slowlygettingthere-我再次更新了我的答案。最后我不得不使用max，因为它没有发挥作用否则非常感谢。

SELECT JobID,JobTitle,[1],[2],[3],[4],[5],[6],[7],[8]
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN([1],[2],[3],[4],[5],[6],[7],[8])) p

DECLARE @locationIDs varchar(200)=''

SELECT @locationIDs+=CONCAT(',[',LocationID,']')
FROM Locations
ORDER BY LocationID

SET @locationIDs=STUFF(@locationIDs,1,1,'')

--PRINT @locationIDs

DECLARE @query varchar(1000)=CONCAT('SELECT JobID,JobTitle,',@locationIDs,'
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN(',@locationIDs,')) p')

--PRINT @query

EXEC(@query)

DECLARE
  @locationIDs varchar(200)='',
  @locationTitles varchar(2000)=''

SELECT
  @locationIDs+=CONCAT(',[',LocationID,']'),
  @locationTitles+=CONCAT(',[',LocationID,'] [',LocationName,']')
FROM Locations
ORDER BY LocationID

SET @locationIDs=STUFF(@locationIDs,1,1,'')
SET @locationTitles=STUFF(@locationTitles,1,1,'')

--PRINT @locationIDs
--PRINT @locationTitles

DECLARE @query varchar(2000)=CONCAT('SELECT JobID,JobTitle,',@locationTitles,'
FROM
  (
    SELECT j.JobID,j.JobTitle,r.LocationID,r.RequestID
    FROM Jobs j
    LEFT JOIN Requests r ON r.JobID=j.JobID
  ) q PIVOT(COUNT(RequestID) FOR LocationID IN(',@locationIDs,')) p')

--PRINT @query

EXEC(@query)