计算SQL Server中某个值连续出现的最大次数

我有一张有球员、成绩和ID的表格：

Player | Result | ID
---------------
An     | W      | 1
An     | W      | 1
An     | L      | 0
An     | W      | 1
An     | W      | 1
An     | W      | 1
Ph     | L      | 0
Ph     | W      | 1
Ph     | W      | 1
Ph     | L      | 0
Ph     | W      | 1

“W”的ID始终为1

我需要创建一个查询来计算每个玩家连续“W”的最大数量：

Player | MaxWinStreak
---------------------
An     | 3    
Ph     | 2

我尝试使用无边界的行，但我只能让它计算总Ws的最大数量，而不是连续的

    Select
    t2.player
    ,max(t2.cumulative_wins) As 'Max'

    From

    (   Select 
            t.Player
            ,Sum(ID) Over (Partition By t.Result,t.player 
             Order By t.GameWeek Rows Unbounded Preceding) As cumulative_wins

        From
             t  

             ) t2

    Group By
    t2.player

---

我可以采取其他方法吗？

您需要一个列来指定顺序。SQL表表示无序集。在下面的查询中，

？

表示此列

您可以使用行号的差异来获得每个连胜：

select player, count(*) as numwins
from (select t.*,
             row_number() over (partition by player order by ?) as seqnum, 
             row_number() over (partition by player, result order by ?) as seqnum_r 
      from t
     ) t
where result = 'W'
group by player, (seqnum - seqnum_r);

然后，您可以获得最大值：

select player, max(numwins)
from (select player, count(*) as numwins
      from (select t.*,
                   row_number() over (partition by player order by ?) as seqnum, 
                   row_number() over (partition by player, result order by ?) as seqnum_r 
            from t
           ) t
      where result = 'W'
      group by player, (seqnum - seqnum_r)
     ) pw
group by player;

---

您需要一个列来指定顺序。是否有任何列存储赢和输的顺序？@GordonLinoff我很乐意添加任何其他列，不知道如何进行此操作，您可以使用

order by（选择1）

？