Sql 查找表1中的值，其中表2中的值位于表1中的行之间

假设以下结构：

项目：

阈值：

我正在使用SQLServer2008根据“PriceThreshold”中的商品价格介于两者之间的位置返回“Reserve”

例如：

ItemId  Reserve
1000    5
2000    10
3000    1

-ItemId 4000的价格不大于最低价格阈值，因此应将其从结果中排除

理想情况下，我只希望能够使用一些直接的T-SQL，但是如果我需要创建一个存储过程来创建一个临时表来存储值，那就好了

已经很晚了，我想我的大脑已经关闭了，所以我非常感谢你的帮助

---

谢谢。

对以下内容感兴趣：

select
  ItemId, 
  (select top 1 Reserve
   from Threshold 
   where Threshold.PriceThreshold < Items.Price
    order by PriceThreshold desc) as Reserve
from
  Items
where
  Price > (select min(PriceThreshold) from Threshold)

---

一种方法是使用保留作为范围的下边界，并使用lead分析函数生成下一个下边界，即上边界

一旦你做到了这一点，你只需要加入一个条件，价格应该在两个边界之间。不幸的是，between运算符不处理null，因此您需要使用一个有点笨拙的条件来处理第一行和最后一行：

SELECT [ItemId], [Reserve]
FROM   Items
JOIN   (SELECT [PriceThreshold] AS [Bottom], 
               LEAD([PriceThreshold]) OVER (ORDER BY [PriceThreshold]) AS [Top],
               [Reserve] 
        FROM   [Threshold]) t ON 
               [Price] Between [Bottom] AND [Top] OR
               ([Top] IS NULL AND [Price] > [Bottom]) OR
               ([Bottom] IS NULL AND [Price] < [Top])

---

您可以使用

select i.itemid, max(lo.pricethreshold) as lo
from items i
join threshold lo on lo.pricethreshold <= i.price
group by i.itemid

然后用这个来检索保留区

with bounds as (select i.itemid, max(lo.pricethreshold) as lo
                from items i
                join threshold lo on lo.pricethreshold <= i.price
                group by i.itemid)
select i.itemid, t.reserve
from items i
join bounds b on b.itemid = i.itemid
join threshold t on t.pricethreshold = b.lo

---

令人惊叹的成功了。我知道有人能帮我摆脱疲惫的大脑。

select i.itemid, max(lo.pricethreshold) as lo
from items i
join threshold lo on lo.pricethreshold <= i.price
group by i.itemid

with bounds as (select i.itemid, max(lo.pricethreshold) as lo
                from items i
                join threshold lo on lo.pricethreshold <= i.price
                group by i.itemid)
select i.itemid, t.reserve
from items i
join bounds b on b.itemid = i.itemid
join threshold t on t.pricethreshold = b.lo