值大于1的单元格的嵌套SQL IN语句

如何编写SQL，使其返回给我

汤姆，肯，杰瑞

我尝试了这个SQL作为

select name
  from staffDB
 where dept in (select value 
                  from ConfigDB 
                 where key = 'dept')

---

但是它不返回值，不，不，我不允许更改数据库设计。

您的数据库设计不是最佳的，因为它存储的是CSV值。也就是说，这里有一种使用LISTAGG 11g+获得所需输出的方法：

请注意，我们使用以下逻辑将配置表中的部门CSV列表与staff表中的每个标量值进行比较，例如：

,A,B,C, LIKE '%,A,%'

---

也就是说，我们在CSV部门字符串上标记逗号，这样我们可以搜索每个可能的标量部门，每个部门都用逗号括起来。

一个选项是用逗号拆分，然后在SELECT中使用LISTAGG函数进行合并。。按级别连接。。声明：

WITH ConfigDB( key, value ) AS
(
 SELECT 'dept', 'A,B,C' FROM dual
), StaffDB( name, dept ) AS
(
 SELECT 'tom'  , 'A' FROM dual UNION ALL
 SELECT 'ken'  , 'B' FROM dual UNION ALL
 SELECT 'jerry', 'C' FROM dual  
), t AS
(
 SELECT REGEXP_SUBSTR(value,'[^,]',1,level) AS letter, level AS lvl
   FROM ConfigDB
  CONNECT BY level <= REGEXP_COUNT(value,',') + 1
)
SELECT LISTAGG(name,',') WITHIN GROUP (ORDER BY lvl) AS DBNAme
  FROM t  
  JOIN StaffDB
    ON dept = letter

---

请使用下面的查询

select * from 
(select LISTAGG(Name, ',') WITHIN GROUP (ORDER BY Dept) as name, 
LISTAGG(Dept, ',') WITHIN GROUP (ORDER BY Dept) as dept from staffDB)
where dept  in
(select value from ConfigDB);

下面是测试用例

---

您可以使用层次结构查询拆分该值，然后按如下方式将其合并：

SQL>  SELECT
2      C.KEY,
3      LISTAGG(S.NAME, ',') WITHIN GROUP(ORDER BY S.DEPT) DEPARTMENTS
4     FROM
5      CONFIGDB   C
6      CROSS JOIN TABLE ( CAST(MULTISET(
7          SELECT REGEXP_SUBSTR(C.VALUE, '[^,]+', 1, LEVEL)
8            FROM DUAL
9          CONNECT BY LEVEL <= REGEXP_COUNT(C.VALUE, '[^,]+')
10      ) AS SYS.ODCIVARCHAR2LIST) ) C1
11      LEFT JOIN STAFFDB    S ON S.DEPT = C1.COLUMN_VALUE
12    GROUP BY C.KEY;

KEY   DEPARTMENTS
----- ---------------
dept  tom,ken,jerry

SQL>

SQL>  SELECT
2      C.KEY,
3      LISTAGG(S.NAME, ',') WITHIN GROUP(ORDER BY S.DEPT) DEPARTMENTS
4     FROM
5      CONFIGDB   C
6      CROSS JOIN TABLE ( CAST(MULTISET(
7          SELECT REGEXP_SUBSTR(C.VALUE, '[^,]+', 1, LEVEL)
8            FROM DUAL
9          CONNECT BY LEVEL <= REGEXP_COUNT(C.VALUE, '[^,]+')
10      ) AS SYS.ODCIVARCHAR2LIST) ) C1
11      LEFT JOIN STAFFDB    S ON S.DEPT = C1.COLUMN_VALUE
12    GROUP BY C.KEY;

KEY   DEPARTMENTS
----- ---------------
dept  tom,ken,jerry

SQL>