Sql 使用Oracle将三个表与PIVOT合并为一个表

Sql 使用Oracle将三个表与PIVOT合并为一个表,sql,oracle,Sql,Oracle,我有三个Oracle SQL select查询,它们返回以下结果。 第一次选择查询返回结果: user_id | user_name | ---------|-----------| 1 | user_1 | 2 | user_2 | 3 | user_3 | 4 | user_4 | exam_id | exam_name | ---------|-----------| 1 | exam_

我有三个Oracle SQL select查询,它们返回以下结果。 第一次选择查询返回结果:

 user_id | user_name |
---------|-----------|
     1   |   user_1  |
     2   |   user_2  |
     3   |   user_3  |
     4   |   user_4  |
 exam_id | exam_name |
---------|-----------|
    1    |   exam_1  |
    2    |   exam_2  |
    3    |   exam_3  |
 exam_id | user_id | exam_date |
---------|---------|-----------|
    1    |    1    |    2017   |
    1    |    2    |    2018   |
    1    |    3    |    2017   |
    2    |    3    |    2018   |
第二个select查询返回结果:

 user_id | user_name |
---------|-----------|
     1   |   user_1  |
     2   |   user_2  |
     3   |   user_3  |
     4   |   user_4  |
 exam_id | exam_name |
---------|-----------|
    1    |   exam_1  |
    2    |   exam_2  |
    3    |   exam_3  |
 exam_id | user_id | exam_date |
---------|---------|-----------|
    1    |    1    |    2017   |
    1    |    2    |    2018   |
    1    |    3    |    2017   |
    2    |    3    |    2018   |
第三个select查询返回结果:

 user_id | user_name |
---------|-----------|
     1   |   user_1  |
     2   |   user_2  |
     3   |   user_3  |
     4   |   user_4  |
 exam_id | exam_name |
---------|-----------|
    1    |   exam_1  |
    2    |   exam_2  |
    3    |   exam_3  |
 exam_id | user_id | exam_date |
---------|---------|-----------|
    1    |    1    |    2017   |
    1    |    2    |    2018   |
    1    |    3    |    2017   |
    2    |    3    |    2018   |
我希望将这些查询合并以获得结果:

 user_id | user_name | exam_1 | exam_2 | exam_3 |
---------|-----------|--------|--------|--------|
     1   |   user_1  |  2017  |        |        |
     2   |   user_2  |  2018  |        |        |
     3   |   user_3  |  2017  |  2018  |        |
     4   |   user_4  |        |        |        |
如果有任何帮助,我将不胜感激


谢谢你@shrek在这里帮助我。我设法为透视值创建变量,但无法将变量放入透视中。因此,我得到了这方面的帮助,最终版本(针对11g)如下所示:

variable x REFCURSOR
DECLARE
    exam_ids   VARCHAR2(255);
BEGIN
    SELECT
        LISTAGG(''''
                  || exam_id
                  || ''' AS "'
                  || exam_name
                  || '"',',') WITHIN GROUP(
            ORDER BY
                exam_id ASC
        )
    INTO exam_ids
    FROM
        exam;

    OPEN :x FOR 'SELECT
        *
               FROM
        (
            SELECT
                u.user_id,
                u.user_name,
                e.exam_id,
                eu.exam_date
            FROM
                users u
                LEFT JOIN exam_user eu ON u.user_id = eu.user_id
                LEFT JOIN exam e ON e.exam_id = eu.exam_id
            ORDER BY
                u.user_id
        )
            PIVOT ( MAX ( exam_date )
                FOR exam_id
                IN ( ' || EXAM_IDS || ' )
            )
    ORDER BY
        1';
END;
/

print x


这在SQL开发人员和SQL*Plus中都可以使用。但在尝试将数据库与PHP文件一起使用时,情况并非如此。为此,我需要创建一个过程,然后可以从PHP文件中调用该过程。尝试使用PHP文件中的上述代码和解决方案时出现问题。

这应该可以让您继续-

CREATE TABLE users
    (user_id varchar2(9), user_name varchar2(11))
;

INSERT ALL 
    INTO users (user_id, user_name)
         VALUES ('1', 'user_1')
    INTO users (user_id, user_name)
         VALUES ('2', 'user_2')
    INTO users (user_id, user_name)
         VALUES ('3', 'user_3')
    INTO users (user_id, user_name)
         VALUES ('4', 'user_4')
SELECT * FROM dual
;

CREATE TABLE exam
    (exam_id varchar2(9), exam_name varchar2(11))
;

INSERT ALL 
    INTO exam (exam_id, exam_name)
         VALUES ('1', 'exam_1')
    INTO exam (exam_id, exam_name)
         VALUES ('2', 'exam_2')
    INTO exam (exam_id, exam_name)
         VALUES ('3', 'exam_3')
SELECT * FROM dual
;

CREATE TABLE exam_user
    (exam_id varchar2(9), user_id varchar2(9), exam_date varchar2(11))
;

INSERT ALL 
    INTO exam_user (exam_id, user_id, exam_date)
         VALUES ('1', '1', '2017')
    INTO exam_user (exam_id, user_id, exam_date)
         VALUES ('1', '2', '2018')
    INTO exam_user (exam_id, user_id, exam_date)
         VALUES ('1', '3', '2017')
    INTO exam_user (exam_id, user_id, exam_date)
         VALUES ('2', '3', '2018')
SELECT * FROM dual
;
查询-

SELECT * FROM (
SELECT U.USER_ID, U.USER_NAME, E.EXAM_NAME,EU.EXAM_DATE
FROM USERS U, EXAM E, EXAM_USER EU
WHERE U.USER_ID = EU.USER_ID(+)
AND E.EXAM_ID(+) = EU.EXAM_ID
ORDER BY U.USER_ID
  )
  PIVOT (MAX(EXAM_DATE) FOR EXAM_NAME IN ('exam_1' as exam_1, 'exam_2' as exam_2,'exam_3' as exam_3))
  order by 1
;
输出-


到目前为止,你尝试过什么?我尝试过将这3个结果放到一个表中,我想我可能可以从中拉出最后一个透视表,但我也没有做到。一个很好的答案。直到连接使用的逗号。您应该学会使用明确、正确、标准的
JOIN
语法。感谢您的反馈,我将继续尝试。