编写适当的SQL查询，以确定哪个唱片集的播放长度（总曲目持续时间）最长

我试着和我的讲座一样，但不起作用 表格输入：

查询：

SELECT T1.TRACK_NAME, T1.TRACK_DURATION
FROM TRACKS T1 
INNER JOIN TRACKS T2 ON T1.TRACK_ID = T2.TRACK_ID
WHERE T1.TRACK_DURATION = T2.TRACK_DURATION
ORDER BY T1.TRACK_DURATION;


SELECT T1.TRACK_NAME, T1.TRACK_DURATION
FROM TRACKS T1 
INNER JOIN TRACKS T2 ON T1.TRACK_ID = T2.TRACK_ID
WHERE T1.TRACK_DURATION = T2.TRACK_DURATION
ORDER BY T1.TRACK_DURATION;

它们显示了所有的轨迹和持续时间

这项工作是： 但样本结果必须是这样的：

  TRACK_NAME TRACK_DURATION
   Find You    3,5 
   Friends.    3,5 
   Silence     3,5 
   Rain         4 
   What About Us 4

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根据您问题的标题，此查询将为您提供专辑的标题和总持续时间，其中曲目的总持续时间最长：

SELECT TOP 1 ALBUM_TITLE, SUM(TRACK_DURATION) AS TotalDuration 
FROM ALBUMS a 
    INNER JOIN ALBUM_TRACKS at ON at.ALBUM_ID = a.ALBUM_ID
    INNER JOIN TRACKS t ON t.TRACK_ID = at.TRACK_ID
GROUP BY ALBUM_TITLE
ORDER BY SUM(TRACK_DURATION) DESC

请选择：

select * from tracks as t where exists (
    selecdt 1 from tracks as t2
    where t2.track_id <> t.track_id and t2.track_duration = t.track_duration
)
order by t.track_duration, t.track_name;

select distinct track_name, track_duration
from tracks as t inner join tracks as t2
    on t2.track_id <> t.track_id and t2.track_duration = t.track_duration
order by t.track_duration, t.track_name;

select track_name, track_duration
from tracks
where track_id in (
    select track_id from tracks groups by track_duration having count(*) > 1
)
order by track_duration, track_name;

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需要更多详细信息，如输入预期输出、您使用的逻辑是什么以及最基本的表架构。输出是什么？没有理由将磁道连接到磁道。您的查询甚至不包括albums表，或者至少不包括album_id，这显然很重要。我建议你重新阅读课本和笔记，因为这是一个非常基本的问题。你能帮我解决吗？你问了两个不同的问题。