Sql 在T5_final.tracking_id=T3.tracking_id上 按T1_2.目的地地址_id订购

严格地说，这里没有完全交叉联接，但是您可能有多对多联接。 要跟踪此情况，请尝试查看每个联接，以查看是否有>1个键值

select tracking_id,count(*) from t4 group by 1 having count(*) > 1;
select destination_address_id,count(*) from t1 group by 1 having count(*) > 1;
select tracking_id ,count(*) from t5_final group by 1 having count(*) > 1;

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在返回值的地方，这可能是您的原因。这可能有助于您确定多对多连接的位置。

太多了。简化我想我做不到，我还是个初学者：(

select tracking_id,count(*) from t4 group by 1 having count(*) > 1;
select destination_address_id,count(*) from t1 group by 1 having count(*) > 1;
select tracking_id ,count(*) from t5_final group by 1 having count(*) > 1;