SQL Server存储过程：发出合并两个查询

我希望有人能帮助你解决我遇到的问题。我想在SQL Server中将两个查询合并到一个表中。这是我到达的程序，但在第2季度。[Umrli]弹出未将数据设置为取决于第1季度。[Naziv Ustanove]

ALTER PROCEDURE [dbo].[test]
AS
BEGIN
    SELECT 
        q1.[Naziv ustanove], q1.[Broj lica], q1.[Broj dana lezanja], q2.Umrli
    FROM 
        (SELECT 
             i_bolnica.naziv AS [Naziv ustanove], 
             COUNT (bolnickiracunSve.id) AS [Broj lica], 
             SUM(bolnickiracunSve.br_dana_lezanja) AS [Broj dana lezanja]
         FROM 
             i_bolnica 
         INNER JOIN 
             bolnickiracunSve ON i_bolnica.id = bolnickiracunSve.id_bolnica
         WHERE 
             bolnickiracunSve.id_bolnica < 91 
             AND bolnickiracunSve.id_odeljenje_otpust NOT IN (800,801,802) 
             AND bolnickiracunSve.id_drzavljanstvo IN (688)
             AND dbo.GrupeBolesti(bolnickiracunSve.id_osnovni_uzrok_hospitalizacije) NOT IN ('z%') 
         GROUP BY 
             i_bolnica.naziv)q1
    CROSS JOIN 
        (SELECT 
             i_bolnica.naziv AS [Naziv ustanove], 
             COUNT (bolnickiracunSve.id) AS [Umrli] 
         FROM 
             i_bolnica 
         INNER JOIN 
             bolnickiracunSve ON i_bolnica.id = bolnickiracunSve.id_bolnica
         WHERE 
             bolnickiracunSve.id_bolnica < 91 
             AND bolnickiracunSve.id_odeljenje_otpust NOT IN (800, 801, 802) 
             AND bolnickiracunSve.id_drzavljanstvo IN (688)
             AND dbo.GrupeBolesti(bolnickiracunSve.id_osnovni_uzrok_hospitalizacije) NOT IN ('z%') 
             AND bolnickiracunSve.id_vrsta_otpusta = '6'
         GROUP BY 
             i_bolnica.naziv)q2
END

---

如果我没有弄错，这两个子查询除了where子句之外是相同的。如果是，请使用条件聚合：

SELECT b.naziv AS [Naziv ustanove], 
       COUNT(s.id) AS [Broj lica], 
        SUM(s.br_dana_lezanja) AS [Broj dana lezanja],
       SUM(CASE WHEN s.id_vrsta_otpusta = '6' THEN 1 ELSE 0 END)
FROM i_bolnica b INNER JOIN 
     bolnickiracunSve s
     ON b.id = s.id_bolnica
WHERE s.id_bolnica < 91 AND
      s.id_odeljenje_otpust NOT IN (800, 801, 802) AND
      s.id_drzavljanstvo IN (688) AND
      dbo.GrupeBolesti(s.id_osnovni_uzrok_hospitalizacije) NOT IN ('z%') 
GROUP BY b.naziv;

---

请注意，表别名使查询更易于编写和阅读。

谢谢Gordon这是我想看到的解决方案和答案，在我的情况下，此问题已结束：@ZdravkoLukic如果这回答了您的问题，请选中复选标记✔ 在答案旁边。请在此处阅读有关此礼仪的更多信息：。