Sql Oracle:按请求计数和分组不返回行，而返回0

我有一个查询，它统计满足条件的

acc\u ene

的数量

ene.ene\u type='PRCECO'

和

deal.deal\u scope='Y'

，对于给定的

运行id

以下是查询：

select run.run_id, 35, count(*), sysdate
from dt_runs run
join acc_deals deal on deal.deal_cnt_id = run.deal_cnt_id
join acc_ene ene on ene.deal_id = deal.deal_id and ene.ene_cnt_id = run.ene_cnt_id
where ene.ene_type = 'PRCECO'
and deal.deal_scope = 'Y'
and run.run_id = '&1'
group by run.run_id, 35, sysdate;

但是，当不存在这样的

acc__ene

时，查询将不返回任何行，而不是返回

0

。 有没有办法修改我的查询以使其返回

0

我已经尝试了

nvl（count（*），0）

（>不是更好）和这个查询，它似乎可以工作：

select run.run_id, 34, (select count(*) from acc_ene ene where ene.ene_type = 'PRCECO'), sysdate
from dt_runs run, acc_deals deal, acc_ene ene 
where ene.deal_id = deal.deal_id
and ene.ene_cnt_id = run.ene_cnt_id
and deal.deal_scope = 'Y'
and run.run_id = '&1'
and deal.deal_cnt_id = run.deal_cnt_id 
group by run.run_id, 34, sysdate;

但后来我尝试了另一个

ene.ene_type='IMM'

，我知道表中有记录。它返回类型为

'IMM'

的

acc_ene

的总数，而不是特定运行的此类

acc_ene

---

我做错了什么？

当没有数据时，就没有结果，这就是SQL的工作方式

尝试改为使用外部联接进行更改：

select run.run_id, 35, count(ene.deal_id), sysdate
from dt_runs run
left join acc_deals deal 
  on deal.deal_cnt_id = run.deal_cnt_id
 and deal.deal_scope = 'Y'
left join acc_ene ene
  on ene.deal_id = deal.deal_id 
 and ene.ene_cnt_id = run.ene_cnt_id
 and ene.ene_type = 'PRCECO'
where run.run_id = '&1'
group by run.run_id, 35, sys date;

或者，您只需要一次运行的数据\u id:

select min(run.run_id), 35, count(*), sysdate
from dt_runs run
join acc_deals deal on deal.deal_cnt_id = run.deal_cnt_id
join acc_ene ene on ene.deal_id = deal.deal_id and ene.ene_cnt_id = run.ene_cnt_id
where ene.ene_type = 'PRCECO'
and deal.deal_scope = 'Y'
and run.run_id = '&1';

我无法测试Oracle是否接受没有分组依据的常量，否则您可能必须使用

select min(run.run_id), min(35), count(*), min(sys date)