8.3之前的Postgresql版本的不同行数

我有一个表，它返回给我如下内容：

name   | value
John   | 3
John   | 4
John   | 5
Robert | 10
Robert | 6
Robert | 4

等等

我需要在不同的名称上显示行数，如下所示：

row_num | name   | value
1       | John   | 3
1       | John   | 4
1       | John   | 5
2       | Robert | 10
2       | Robert | 6
2       | Robert | 4

主要的问题是我的Postgres版本是8.2，我现在无法升级，所以在做了研究之后，我发现一些有用的功能在我的版本上是不可用的，比如row_number，generate_series，等等

---

有办法吗？

这适用于您的示例数据：

SELECT
  COALESCE(r.row_num, m.row_max) AS row_num,
  t.name,
  t.value
FROM tmp t
LEFT JOIN (
  SELECT
    r1.name,
    COUNT(*) AS row_num
  FROM (SELECT DISTINCT name FROM tmp) r1
  JOIN (SELECT DISTINCT name FROM tmp) r2 
    ON r1.name > r2.name
  GROUP BY 1) r 
    ON t.name = r.name
LEFT JOIN (
  SELECT
    COUNT(*) AS row_max
  FROM (SELECT DISTINCT name FROM tmp) r3
) m ON True;

select (select count(distinct name) from person p2 where p2.name <= p1.name) as cnt,
       p1.name,
       p1.value
from person p1
order by p1.name;

我只能在9.4上测试它，但我认为它也应该在8.x上工作，但不会很快

SQLFiddle：

---

但您确实应该升级到受支持和维护的版本

使用临时视图模拟子查询和CTE的老把戏：

CREATE TABLE a (name text, val integer);
INSERT INTO a (name , val ) VALUES
 ('John' , 3 )
, ('John' , 4 )
, ('John' , 5 )
, ('Robert' , 10 )
, ('Robert' , 6 )
, ('Robert' , 4 )
    ;
CREATE VIEW d AS SELECT DISTINCT name FROM a;

CREATE VIEW c AS
SELECT d0.name, COUNT(*) AS rnk
FROM d d0
JOIN d d1 ON d1. name <= d0.name
GROUP BY d0.name
    ;

-- SELECT * FROM d;
-- SELECT * FROM c;

SELECT c.rnk, a.name, a.val
FROM a
JOIN c ON a.name = c.name
    ;

DROP VIEW d;
DROP VIEW c;