Sql 将一行除以整列总和

我需要将一个行值（在我的例子中为单位）除以整行总和，得到一个百分比（单位列）。有人能帮我吗？下面是代码和代码的数据结果

    select db.ManufAbbrName Manufacturer, 
       db.ProdName ProductName,
       sum(wk.Units) Units,
       wk.RecordDate RecordDate
  from MDDB db
  join wkdata wk 
    on db.NDC = wk.NDC11 
  join @NDCs nd
    on nd.NDCs = wk.NDC11
 where wk.RecordDate between @StartDate and @EndDate
group by db.ManufAbbrName,
         db.ProdName,
         wk.RecordDate

结果集：

Example1    CLOBETASOL PROPIONATE EMO   264475  2013-11-01 00:00:00.000
Example2    CLOBETASOL PROPIONATE       187371  2013-11-01 00:00:00.000
Example3    OLUX-E                      82154   2013-11-01 00:00:00.000

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所以我需要得到第1行中每个制造商第3列的百分比值。所以对于第一个，264475/534000查看

OVER

子句。这是一篇关于它的文章

一个小例子

DECLARE @t TABLE (group_id CHAR(1), value INT)

INSERT INTO @t (group_id, value)
VALUES ('A', 5),('A', 5), ('A', 5),('B', 5),('B', 5)

SELECT group_id, value, group_total, rate = CASE WHEN group_total = 0 THEN 0 ELSE (1.0*value) / (1.0*group_total) END
FROM (
    SELECT group_id, value, group_total = SUM(value) OVER(PARTITION BY group_id)
    FROM @t
) t

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您要查找的是（x分区）上的

和（y）

用法。 您可以执行以下操作：

SELECT group_id
, value
, SUM(value) OVER(PARTITION BY group_id)
, CASE WHEN SUM(value) OVER(PARTITION BY group_id) = 0 THEN 0 
ELSE (1.0*value) / (1.0*SUM(value) OVER(PARTITION BY group_id)) END as Rate

FROM t

---

**

谢谢！另外，您可以在分区函数中输入多个值吗？@user1049984 Yes just list

partitionby Col1，Col2