以特定时间间隔查询行的MySQL

我对mysql查询感到有些困惑。谢谢你的帮助

我当前的查询：

SELECT
  r.name
, r.network
, i.name
, d.dtime
, d.input
FROM router AS r
INNER JOIN interface AS i
ON r.rid = i.rid
INNER JOIN 1273118400_1_60 AS d
ON i.id = d.id
AND dtime BETWEEN 1273152000 AND 1273153800 WHERE i.status = "active"

现在，我使用Unix_时间戳作为查询的时间间隔。 现在，我得到了以下方面的结果： 1273152000、1273152001、1273152002等等

我想以60秒为间隔，比如： 1273152000、1273152060、1273152120等等

你知道我该怎么做吗

请帮忙。 谢谢,

---

Jillika

我不确定它是否可以进一步简化，但您可能希望尝试以下方法：

SELECT       r.name,
             r.network,
             i.name,
             d.dtime,
             d.input
FROM         router AS r
INNER JOIN   interface AS i ON (r.rid = i.rid)
INNER JOIN   (
                 SELECT      t.dtime, dt.input, dt.id
                 FROM        1273118400_1_60 AS t
                 INNER JOIN  (
                                SELECT dtime, id, input
                                FROM   1273118400_1_60
                             ) AS dt ON (dt.dtime = t.dtime AND dt.id = t.id)
                 GROUP BY    t.dtime DIV 60
             ) AS d ON (i.id = d.id)
WHERE        (d.dtime BETWEEN 1273152000 AND 1273153800) AND 
             (i.status = 'active');

测试用例：

CREATE TABLE router (rid int, name varchar(20), network int);
CREATE TABLE interface (id int, rid int, status varchar(20), name varchar(10));
CREATE TABLE 1273118400_1_60 (id int, dtime int, input int);

INSERT INTO router VALUES (1, 'router A', 0);
INSERT INTO interface VALUES (1, 1, 'active', 'interface A');
INSERT INTO 1273118400_1_60 VALUES (1, 1273151999, 1);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152000, 2);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152001, 3);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152002, 4);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152059, 5);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152060, 6);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152061, 7);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152062, 8);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152119, 9);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152120, 10);
INSERT INTO 1273118400_1_60 VALUES (1, 1273152121, 11);

结果:

+----------+---------+-------------+------------+-------+
| name     | network | name        | dtime      | input |
+----------+---------+-------------+------------+-------+
| router A |       0 | interface A | 1273152000 |     2 |
| router A |       0 | interface A | 1273152060 |     6 |
| router A |       0 | interface A | 1273152120 |    10 |
+----------+---------+-------------+------------+-------+
3 rows in set (0.00 sec)

---

你的问题不太清楚，但无论如何试试这个：

SELECT r.name, r.network, i.name, d.dtime, d.input
FROM router r
INNER JOIN interface i
ON r.rid = i.rid
INNER JOIN 1273118400_1_60 AS d
ON i.id = d.id
WHERE d.time > 1273152000 AND d.time < 1273153800 
AND i.status = "active";

选择r.name、r.network、i.name、d.dtime、d.input
从路由器r
内部连接接口i
关于r.rid=i.rid
内部连接1273118400_1_60作为d
在i.id=d.id上
其中d.time>1273152000和d.time<1273153800
和i.status=“active”；

您好，谢谢您的快速回复。我将尝试更清楚地说明：1273152000=unixtimestamp for:05/07/2010 09:20 1273153800=unixtimestamp for:05/07/2010 09:50我想查询每分钟间隔（60秒），因为我的表包含每秒的值。dtime=unix时间戳中的时间。知道我能做什么吗？嗯，我会考虑创建一个存储函数来处理它，如果它变得比这更复杂的话。

SELECT
r.name
,r.network
,i.name
, d.dtime
, 60*(floor(d.dtime/60)) dtime2
, d.input
FROM router AS r
INNER JOIN interface AS i
ON r.rid = i.rid
INNER JOIN 1273118400_1_60 AS d
ON i.id = d.id
AND dtime BETWEEN 1273152000 AND 1273153800 WHERE i.status = "active"