Sql 根据每个月的日期-时间列分隔行

我在sql server数据库环境中有下表

开始日期MM/DD/YYYY的格式

我需要结果如下表所示

根据“开始日期”列，记录应在“开始日期”和“结束日期”之间的期间内每个月进行分隔

---

您可以使用递归CTE：

with cte as (
      select id, startdate as dte, enddate
      from t
      union all
      select id, 
             dateadd(day, 1, eomonth(dte)),
             enddate
      from t
      where eomonth(dte) < enddate
     )
select id, dte,
       lead(dte, 1, enddate) over (partition by id order by dte)
from cte;

谢谢戈登·林诺夫 使用CTE，我得到了以下结果

我的代码

WITH cte 
     AS (SELECT 1                          AS id, 
                Cast('2010-01-20' AS DATE) AS trg, 
                Cast('2010-01-20' AS DATE) AS strt_dte, 
                Cast('2010-03-15' AS DATE) AS end_dte 
         UNION ALL 
         SELECT id, 
                Dateadd(day, 1, Eomonth (trg)), 
                strt_dte, 
                end_dte 
         FROM   cte 
         WHERE  Eomonth(trg) < end_dte) 
SELECT id, 
       trg, 
       strt_dte, 
       end_dte, 
       Lead (trg, 1, end_dte) 
         OVER ( 
           partition BY id 
           ORDER BY trg) AS lead_result 
FROM   cte 

---

列[开始日期]和[结束日期]是什么类型？两列的类型都是datetime