在SQL中将日期拆分为两列(日期和时间)
我正在尝试将表中的数字日期键转换为日期时间键。我目前的查询是:在SQL中将日期拆分为两列(日期和时间),sql,sql-server,sql-server-2008,Sql,Sql Server,Sql Server 2008,我正在尝试将表中的数字日期键转换为日期时间键。我目前的查询是: SELECT DATEADD(HOUR,-4,CONVERT(DATETIME,LEFT([Date],8)+' '+ SUBSTRING([Date],10,2)+':'+ SUBSTRING([Date],12,2)+':'+ SUBSTRING([Date],14,2)+'.'+ SUBSTRING([Date],15,3))) [Date], [Object] AS [Dataset], S
SELECT
DATEADD(HOUR,-4,CONVERT(DATETIME,LEFT([Date],8)+' '+
SUBSTRING([Date],10,2)+':'+
SUBSTRING([Date],12,2)+':'+
SUBSTRING([Date],14,2)+'.'+
SUBSTRING([Date],15,3))) [Date],
[Object] AS [Dataset],
SUBSTRING(Parms,1,6) AS [Media]
FROM (Select CONVERT(VARCHAR(18),[Date]) [Date],
[Object],
MsgId,
Parms
FROM JnlDataSection) A
Where MsgID = '325' AND
SUBSTRING(Parms,1,6) = 'V40449'
Order By Date DESC;
“日期”列显示以下内容:
2013-06-22 13:36:44.403
我想将其分为两列:
日期:
2013-06-22
时间(以微秒计):
13:36:44
有人可以修改我现有的查询以显示所需的输出吗?我们将不胜感激。请注意:我正在使用SQL Server Management Studio 2008。您可能需要研究convert()函数:
select convert(date, getdate()) as [Date], convert(varchar(8), convert(time, getdate())) as [Time]
给予
Date Time
---------- --------
2013-07-16 15:05:43
在原始SQL的基础上进行包装,会产生公认的非常糟糕的结果:
SELECT convert(date,
DATEADD(HOUR,-4,CONVERT(DATETIME,LEFT([Date],8)+' '+
SUBSTRING([Date],10,2)+':'+
SUBSTRING([Date],12,2)+':'+
SUBSTRING([Date],14,2)+'.'+
SUBSTRING([Date],15,3)))) [Date],
convert(varchar(8), convert(time,
DATEADD(HOUR,-4,CONVERT(DATETIME,LEFT([Date],8)+' '+
SUBSTRING([Date],10,2)+':'+
SUBSTRING([Date],12,2)+':'+
SUBSTRING([Date],14,2)+'.'+
SUBSTRING([Date],15,3))))) [Time],
[Object] AS [Dataset],
SUBSTRING(Parms,1,6) AS [Media]
FROM (Select CONVERT(VARCHAR(18),[Date]) [Date],
[Object],
MsgId,
Parms
FROM JnlDataSection) A
Where MsgID = '325' AND
SUBSTRING(Parms,1,6) = 'V40449'
Order By Date DESC;
您可能希望将其中的一部分移动到视图中,以降低复杂性。您可以使用:
结果:
Date_AsVarChar Date_AsDateTime OnlyDate OnlyTime
-------------------- ----------------------- ---------- --------
20130622133644403 2013-06-22 13:36:44.403 2013-06-22 13:36:44
解决方案:
SELECT
CONVERT(DATE,y.Date_AsDateTime) AS OnlyDate,
CONVERT(TIME(0),y.Date_AsDateTime) AS OnlyTime
FROM(
SELECT [Object], MsgId, Parms,
CONVERT(DATETIME, STUFF(STUFF(STUFF(STUFF(x.[Date],9,0,' '),12,0,':'),15,0,':'),18,0,'.')) AS Date_AsDateTime
FROM JnlDataSection
) A
WHERE MsgID = '325'
-- SUBSTRING(Parms,1,6) = 'V40449' is not SARG-able
AND Parms LIKE 'V40449%'
ORDER BY DATE DESC;
使用以下场景获取日期、时间、日、月、年、小时、分钟、秒、AM/PM:
select
UpdatedOn , CONVERT(varchar,UpdatedOn,100) DateTime, CONVERT(varchar,UpdatedOn,10) Date ,
CONVERT(varchar,UpdatedOn,108) Time , substring(CONVERT(varchar,UpdatedOn,106),1,2) Day,
substring(CONVERT(varchar,UpdatedOn,106),4,3) CMonth,
substring(CONVERT(varchar,UpdatedOn,105),4,2)
NMonth, substring(CONVERT(varchar,UpdatedOn,106),8,4) Year,
left(right(CONVERT(varchar,UpdatedOn,100),7),2) Hours_12,
substring(CONVERT(varchar,UpdatedOn,108),1,2) Hours_24,
substring(CONVERT(varchar,UpdatedOn,108),4,2) Minutes,
substring(CONVERT(varchar,UpdatedOn,108),7,2) Second, right(CONVERT(varchar,UpdatedOn,100),2)
AM_PM
from
dbo.DeviceAssignSim where AssignSimId=55;
如何让它显示问题所需的输出?用原始SQL中的[Date]字段替换getdate()。我将稍微更新答案,以包含您的原始问题。我将在我的查询中添加这些问题?您是否可以将其添加到我现有的查询中,然后将其作为答案发布,这样我就可以立即对其进行测试。您能否说明源数据中的[Date]列是什么,这样我就可以对其进行测试?Ta.最初为20130622.133644403。但到目前为止,我已将其转换为2013-06-22 13:36:44.403。您是否可以将该逻辑添加到我现有的查询中?只显示OnlyDate和OnlyTime?大多数情况下,这是一个简单的答案。谢谢
SELECT CONVERT(DATE,[Date])
SELECT CONVERT(TIME(0),[Date])
select
UpdatedOn , CONVERT(varchar,UpdatedOn,100) DateTime, CONVERT(varchar,UpdatedOn,10) Date ,
CONVERT(varchar,UpdatedOn,108) Time , substring(CONVERT(varchar,UpdatedOn,106),1,2) Day,
substring(CONVERT(varchar,UpdatedOn,106),4,3) CMonth,
substring(CONVERT(varchar,UpdatedOn,105),4,2)
NMonth, substring(CONVERT(varchar,UpdatedOn,106),8,4) Year,
left(right(CONVERT(varchar,UpdatedOn,100),7),2) Hours_12,
substring(CONVERT(varchar,UpdatedOn,108),1,2) Hours_24,
substring(CONVERT(varchar,UpdatedOn,108),4,2) Minutes,
substring(CONVERT(varchar,UpdatedOn,108),7,2) Second, right(CONVERT(varchar,UpdatedOn,100),2)
AM_PM
from
dbo.DeviceAssignSim where AssignSimId=55;