在sql中使用count

我需要一个SQL语句，要求是：有一个表，它有两列：ID，Owner\u ID；我插入了几条记录，例如：

ID    Owner_ID
0         0
1         0
2         1
3         1
4         2
5         3
6         3
7         3
8         3
9         0

现在我需要一个SQL语句，它返回一个ID列表，该列表按不同用户拥有的行数从大到小排序。在本例中，所有者3有四行；所有者0有三行，所有者1有两行；所有者2有一行。结果应该是

ID    Owner_ID
5         3
6         3
7         3
8         3
0         0
1         0
9         0
2         1
3         1
4         2

我想我应该使用聚合函数count，有人知道吗

我正在使用HSQLDB

---

提前谢谢

这是非常直截了当的

SELECT
  ID,
  Owner_ID
FROM
  TheTable t
ORDER BY
  (SELECT COUNT(*) FROM TheTable i WHERE i.Owner_ID = t.Owner_ID) DESC

---

这是非常直截了当的

SELECT
  ID,
  Owner_ID
FROM
  TheTable t
ORDER BY
  (SELECT COUNT(*) FROM TheTable i WHERE i.Owner_ID = t.Owner_ID) DESC

---

是的，你有大概的想法。请尝试以下查询：

select t.ID, t.Owner_ID
from table t
inner join (select Owner_ID, count(*) c from table t group by Owner_ID) tc
  on t.Owner_ID = tc.Owner_ID
order by
  tc.c desc, t.ID asc

---

是的，你有大概的想法。请尝试以下查询：

select t.ID, t.Owner_ID
from table t
inner join (select Owner_ID, count(*) c from table t group by Owner_ID) tc
  on t.Owner_ID = tc.Owner_ID
order by
  tc.c desc, t.ID asc

---

这将适用于大多数SQL DBMS，但会显示计数值

SELECT ID, Owner_ID, Owner_Count
  FROM AnonymousTable AS A
  JOIN (SELECT Owner_ID, COUNT(*) AS Owner_Count
          FROM AnonymousTable
         GROUP BY Owner_ID
       ) AS B ON B.Owner_ID = A.Owner_ID
 ORDER BY Owner_Count DESC, Owner_ID ASC, ID ASC;

这将适用于部分但不一定全部DBMS；它按结果列表中未显示的列排序：

SELECT ID, Owner_ID
  FROM AnonymousTable AS A
  JOIN (SELECT Owner_ID, COUNT(*) AS Owner_Count
          FROM AnonymousTable
         GROUP BY Owner_ID
       ) AS B ON B.Owner_ID = A.Owner_ID
 ORDER BY Owner_Count DESC, Owner_ID ASC, ID ASC;

---

这将适用于大多数SQL DBMS，但会显示计数值

SELECT ID, Owner_ID, Owner_Count
  FROM AnonymousTable AS A
  JOIN (SELECT Owner_ID, COUNT(*) AS Owner_Count
          FROM AnonymousTable
         GROUP BY Owner_ID
       ) AS B ON B.Owner_ID = A.Owner_ID
 ORDER BY Owner_Count DESC, Owner_ID ASC, ID ASC;

这将适用于部分但不一定全部DBMS；它按结果列表中未显示的列排序：

SELECT ID, Owner_ID
  FROM AnonymousTable AS A
  JOIN (SELECT Owner_ID, COUNT(*) AS Owner_Count
          FROM AnonymousTable
         GROUP BY Owner_ID
       ) AS B ON B.Owner_ID = A.Owner_ID
 ORDER BY Owner_Count DESC, Owner_ID ASC, ID ASC;

---

哪个数据库管理系统？如图所示，在纯SQL中生成结果需要一个DBMS，该DBMS允许您按选择列表中不存在的计算列排序，这不是标准的SQL功能。哪个DBMS？如图所示，在纯SQL中生成结果需要一个DBMS，该DBMS允许您按选择列表中不存在的计算列排序，这不是标准的SQL功能。或者，也可以按表i中的选择计数*排序，其中i.Owner\u ID=t.Owner\u ID DESC，Owner\u ID，ID？@Andy:如果您愿意的话。OP没有指定任何组内排序，但这应该很容易理解：或者从表i中选择COUNT*，其中i.Owner\u ID=t.Owner\u ID DESC，Owner\u ID，ID？@Andy:如果你愿意的话。OP没有指定任何组内排序，但这应该很容易理解：