如何编写SQL查询以查找每月至少购买两次的客户

我有一个表，列有order\u id、customer\u id、order\u date和Amount

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如何找到从1月到12月每月至少订购2次SQL的客户？

我想您正在寻找这样的客户

select
    order_date_year,
    customer_id
from 
(
    select  
        year(order_date) as order_date_year,
        month(order_date) as order_date_month,
        customer_id,
        count(*) as number_of_orders
    from
        tableName
    group by
        year(order_date),
        month(order_date),
        customer_id
    having
        count(*) >= 2
) as t
group by
    order_date_year,
    customer_id
having
    count(*) = 12

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我想你在找这样的东西

select
    order_date_year,
    customer_id
from 
(
    select  
        year(order_date) as order_date_year,
        month(order_date) as order_date_month,
        customer_id,
        count(*) as number_of_orders
    from
        tableName
    group by
        year(order_date),
        month(order_date),
        customer_id
    having
        count(*) >= 2
) as t
group by
    order_date_year,
    customer_id
having
    count(*) = 12

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标记DBMS，即MySQL、SQL Server等。。您正在使用的。每个月或每个月..？标准1：客户应在1月至12月期间每月购买标准2：对于每个月，客户应至少交易两次标记DBMS，即MySQL、SQL Server等。。您正在使用的。每个月或每个月..？标准1：客户应在1月至12月期间每月购买标准2：对于每个月，客户应至少交易两次