SQL Server-基于案例的透视语句
我有一张这样的桌子:SQL Server-基于案例的透视语句,sql,sql-server,pivot,case,Sql,Sql Server,Pivot,Case,我有一张这样的桌子: Store Holiday Date_Index Temp 123 XMAS t_0 34.9 234 XMAS t_1 M 123 XMAS t_1 22.3 123 XMAS t_2 28.5 Store Holiday t_0 t_1 t_2
Store Holiday Date_Index Temp
123 XMAS t_0 34.9
234 XMAS t_1 M
123 XMAS t_1 22.3
123 XMAS t_2 28.5
Store Holiday t_0 t_1 t_2
123 XMAS 34.9 22.3 28.5
234 XMAS 32.1 NULL 29.5
Select *
from
(
select Store, Holiday, Date_Index,
CASE WHEN ISNumeric(Temp) = 1 THEN CAST(Temp AS DECIMAL(10, 2)) ELSE 0 END AS Temp
from myTable
) as t
PIVOT
(
sum(Temp)
FOR DATE_INDEX IN ([t_0],[t_1],[t_2])
) as P;
我正试图将其转向如下内容:
Store Holiday Date_Index Temp
123 XMAS t_0 34.9
234 XMAS t_1 M
123 XMAS t_1 22.3
123 XMAS t_2 28.5
Store Holiday t_0 t_1 t_2
123 XMAS 34.9 22.3 28.5
234 XMAS 32.1 NULL 29.5
Select *
from
(
select Store, Holiday, Date_Index,
CASE WHEN ISNumeric(Temp) = 1 THEN CAST(Temp AS DECIMAL(10, 2)) ELSE 0 END AS Temp
from myTable
) as t
PIVOT
(
sum(Temp)
FOR DATE_INDEX IN ([t_0],[t_1],[t_2])
) as P;
通过使用:
Select *
from
(
select Store, Holiday, Date_Index, Temp
from myTable
)
PIVOT
(
sum(CASE WHEN ISNUMERIC(Temp) = 1 THEN cast(Temp as decimal) ELSE NULL END)
FOR DATE_INDEX IN ([t_0],[t_1],[t_2])
) as PivotTable;
我的问题是Temp列包含字母和数字的混合。我试图以case语句的总和为中心,但收到了一条错误消息。如何正确补偿非数字字符?一种方法是:不直接从表中选择/旋转,而是从CTE中选择,该CTE将所有非数字
Temp
值替换为NULL一种方法是:不直接从表中选择/旋转,从CTE中选择,该CTE将所有非数值的Temp
值替换为NULL
您不能这样做。但是,您可以在锚查询中这样做:
Store Holiday Date_Index Temp
123 XMAS t_0 34.9
234 XMAS t_1 M
123 XMAS t_1 22.3
123 XMAS t_2 28.5
Store Holiday t_0 t_1 t_2
123 XMAS 34.9 22.3 28.5
234 XMAS 32.1 NULL 29.5
Select *
from
(
select Store, Holiday, Date_Index,
CASE WHEN ISNumeric(Temp) = 1 THEN CAST(Temp AS DECIMAL(10, 2)) ELSE 0 END AS Temp
from myTable
) as t
PIVOT
(
sum(Temp)
FOR DATE_INDEX IN ([t_0],[t_1],[t_2])
) as P;
我使用内置函数将这些非数值替换为0,并将整列转换为轴之前的十进制。然后在pivot
中,只需使用SUM(temp)
结果:
| Store | Holiday | t_0 | t_1 | t_2 |
|-------|---------|--------|------|--------|
| 123 | XMAS | 34.9 | 22.3 | 28.5 |
| 234 | XMAS | (null) | 0 | (null) |
你不能那样做。但是,您可以在锚查询中这样做:
Store Holiday Date_Index Temp
123 XMAS t_0 34.9
234 XMAS t_1 M
123 XMAS t_1 22.3
123 XMAS t_2 28.5
Store Holiday t_0 t_1 t_2
123 XMAS 34.9 22.3 28.5
234 XMAS 32.1 NULL 29.5
Select *
from
(
select Store, Holiday, Date_Index,
CASE WHEN ISNumeric(Temp) = 1 THEN CAST(Temp AS DECIMAL(10, 2)) ELSE 0 END AS Temp
from myTable
) as t
PIVOT
(
sum(Temp)
FOR DATE_INDEX IN ([t_0],[t_1],[t_2])
) as P;
我使用内置函数将这些非数值替换为0,并将整列转换为轴之前的十进制。然后在pivot
中,只需使用SUM(temp)
结果:
| Store | Holiday | t_0 | t_1 | t_2 |
|-------|---------|--------|------|--------|
| 123 | XMAS | 34.9 | 22.3 | 28.5 |
| 234 | XMAS | (null) | 0 | (null) |
这里有另一种方法,可能是更简单的方法-
SELECT Store
,Holiday
,MAX(CASE WHEN Date_Index = 't_0' THEN Temp END) AS t_0
,MAX(CASE WHEN Date_Index = 't_1' THEN Temp END) AS t_1
,MAX(CASE WHEN Date_Index = 't_2' THEN Temp END) AS t_2
FROM YOUR_TABLE
GROUP BY Store
,Holiday
这里有另一种方法,可能是更简单的方法-
SELECT Store
,Holiday
,MAX(CASE WHEN Date_Index = 't_0' THEN Temp END) AS t_0
,MAX(CASE WHEN Date_Index = 't_1' THEN Temp END) AS t_1
,MAX(CASE WHEN Date_Index = 't_2' THEN Temp END) AS t_2
FROM YOUR_TABLE
GROUP BY Store
,Holiday