从UPDATE命令SQL引用外部派生表

我需要在UPDATE命令中从查询中引用cartProduct派生表。有人能解释一下我做错了什么，我怎样才能纠正它吗

UPDATE memberships SET points = (points + COALESCE( 
    (SELECT pts 
    FROM (
        SELECT pid0, SUM (S) as Pts
        FROM ( 
            (SELECT pid0, SUM (pts1) as S
            FROM 
                (SELECT DISTINCT pid0, pid0,pts1
                FROM cartProduct
                WHERE pid0 = i1) as pointsForPath 
            GROUP BY pid0)) as allPtsTbl
        GROUP BY pid0) as temp 
    WHERE memberships.cid = 57010 AND memberships.pid = temp.pid0 ),
0))
FROM (
    SELECT t0.pid as pid0,t1.pid as pid1,t1.invitedby as i1,t1.points as pts1, t2.pid as pid2,t2.invitedby as i2,t2.points as pts2,t3.pid as pid3,t3.invitedby as i3, t3.points as pts3
    FROM memberships t0, memberships  t1, memberships  t2, memberships  t3
    WHERE t0.cid = t1.cid AND t1.cid = t2.cid AND t2.cid = t3.cid) as cartProduct;

这个查询必须做什么并不重要，因为这是一个复杂的查询，我想优化它。我唯一的问题是如何从更新子查询中引用cartProduct。 我要优化的查询是由C代码生成的。。。正如你所看到的，我必须多次计算相同的东西。这个查询只有3个派生表，但也可能是100多个，然后我必须等待10个多小时才能计算出来

UPDATE memberships SET points = points + COALESCE((
SELECT pts 
FROM (
    SELECT pid0, SUM (S) as Pts
    FROM ( 
        SELECT pid0, SUM (pts1) as S
        FROM 
            (SELECT DISTINCT pid0, pid1,pts1
            FROM (
                SELECT t0.pid as pid0, t1.pid as pid1, t1.invitedby as i1, t1.points as pts1 
                FROM memberships t0, memberships t1
                WHERE t0.cid = 57010 AND t1.cid = 57010) as paths
            WHERE pid0 = i1) as pointsForPath
        GROUP BY pid0
        UNION ALL
        SELECT pid0, SUM (pts2) as S
        FROM (
            SELECT DISTINCT pid0, pid2,pts2
            FROM (
                SELECT t0.pid as pid0, t1.pid as pid1, t1.invitedby as i1, t1.points as pts1 , t2.pid as pid2, t2.invitedby as i2, t2.points as pts2 
                FROM memberships t0, memberships t1, memberships t2
                WHERE t0.cid = 57010 AND t1.cid = 57010 AND t2.cid = 57010) as paths
            WHERE pid0 = i1 AND pid1 = i2) as pointsForPath
        GROUP BY pid0
        UNION ALL
        SELECT pid0, SUM (pts3) as S
        FROM (
            SELECT DISTINCT pid0, pid3,pts3
            FROM (
                SELECT t0.pid as pid0, t1.pid as pid1, t1.invitedby as i1, t1.points as pts1 , t2.pid as pid2, t2.invitedby as i2, t2.points as pts2 , t3.pid as pid3, t3.invitedby as i3, t3.points as pts3 
                FROM memberships t0, memberships t1, memberships t2, memberships t3
                WHERE t0.cid = 57010 AND t1.cid = 57010 AND t2.cid = 57010 AND t3.cid = 57010) as paths
            WHERE pid0 = i1 AND pid1 = i2 AND pid2 = i3) as pointsForPath
        GROUP BY pid0 ) as allPtsTbl
GROUP BY pid0) as temp WHERE memberships.cid = 57010 AND memberships.pid = temp.pid0 ),0)

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很抱歉我的英语不好，非常感谢。

如果性能是您的问题，您可以尝试：

update memberships
    set points = points + coalesce(s.points, 0)
    from (nasty union all'ed subquery) s
    where memberships.id = s.id

（假设将pid0字段重命名为id。）

你应该考虑以下几点：

学习正确的连接语法。在“where”从句中做连接变得过时了，就像在英语中使用“hads”或“e”一样。通过选择特定的值（您正在做的事情）隐式地进行连接是非常危险的，因为您不知道从每个表中提取了多少条记录，并且对查询进行一个小的更改可能会产生不利影响（例如选择两个用户而不是一个用户）

将讨厌的子查询放入临时表中。通常，我不主张使用临时表，但这可能会使优化器感到困惑（这在混合选择、删除和更新的查询中尤其可能）

你为什么要在小组讨论之前做一个独特的讨论。首先，您可以执行“sum（distinct）”，尽管这几乎没有必要。这表明连接存在问题。而且，错误的连接会导致查询无法完成

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如果我错了，我很抱歉，但是你的问题看起来一团糟。我会先用using语句重构它。@PreetSangha-你是说

WITH

语句吗？如果你能解释查询试图做什么，并提供输入和预期输出的示例，那么帮助你就容易多了。@GordonLinoff我编辑了我的问题。我希望我能清楚地解释我想做什么。非常感谢，非常感谢。禁止我使用临时表或视图。有没有办法生成只计算一次路径（最长的一个子查询）的查询？这取决于您使用的数据库。对于SQL Server，您将使用递归CTE。对于Oracle，使用“连接方式”语句。但是，您可以选择在应用程序中执行此操作，为每个级别执行多个update语句。