使用ORACLE/SQL根据单个表中的两个条件创建两个单独的列

我有一张像这样的桌子

A1 A2 A3 A4 A5 A6 
1  1   1  1  1  1
2  2   2  2  2  2
3  3   3  3  3  3

我想做这样的任务：

SELECT A2 AS B2 WHERE A1 = 1
SELECT A2 AS B3 WHERE A1 = 2

---

我该怎么做

我认为您可以使用如下查询：

SELECT 
    CASE WHEN A1 = 1 THEN A2 END As B2,
    CASE WHEN A1 = 2 THEN A2 END As B3,
FROM
    yourTable;

---

请注意，

B2

与

A2

相同，如果

A1=1

则为

null

，依此类推。

您得到答案了吗？

SELECT 
    CASE WHEN A1 = 1 THEN A2 END As B2,
    CASE WHEN A1 = 2 THEN A2 END As B3
FROM TABLE_NAME
WHERE  A1 = 1 OR A1 = 2