Sql 如果满足第一个GROUPBY子句，如何合并行

我有一个简单的查询，可以按员工为每个位置提取集合

假设我有以下数据：

Username   Store_number   Invoice_amt
TJ1          1                5
TJ1          1                5
TJ1          2                5
RB2          3                5
RB2          3                5
DD1          4                5
DD1          4                5

我有一个问题：

Select username, Sum(invoice_amt) as Total, Store_number

我将获得以下输出：

username    Total      store_number
TJ1          10          1
TJ1          5           2
RB2          10          3
DD1          10          4

我想做的是——首先合并用户名，然后按门店号将其拆分——有没有办法让我的输出：

username    Total      store_number
TJ1          15          1
RB2          10          3
DD1          10          4

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您可以只取

min（门店号）

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如果我没弄错你的问题，这就是你的问题

Select 
username,
sum(invoice_amt) as Total,
Min(store_number) as store_number
from Table!
Group By UserName

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我知道你可能不想要最小的商店。您可能想要存储最常见的值。如果是：

select username, amount,
       max(case when seqnum = 1 then store end) as most_common_store
from (select username, store, sum(invoice_amount) as amount,
             row_number() over (partition by username order by sum(invoice_amount) desc) as seqnum
      from t
      group by username, store
     ) us
group by username;

select username, amount,
       max(case when seqnum = 1 then store end) as most_common_store
from (select username, store, sum(invoice_amount) as amount,
             row_number() over (partition by username order by sum(invoice_amount) desc) as seqnum
      from t
      group by username, store
     ) us
group by username;